Question

3x^2 – 2x + 7 = 0, then (x -1/3)^2

Answer 1

$3x^{2} - 2x + 7 = 0 \\ \\ y = (x- \frac{1}{3})^{2} \\ \\ y = x^{2} - \frac{2}{3}x + \frac{1}{9} \\ \\ 3y = 3x^{2} - 2x + \frac{1}{3} \\ \\ 3y = 3x^{2} - 2x + 7 - \frac{20}{3} \\ \\ 3y = 0 - \frac{20}{3} \\ \\ 3y = - \frac{20}{3} \\ \\ \boxed{y =-\frac{20}{9}}$