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kvv77 [185]
3 years ago
4

A youth group is setting up camp. Rain is predicted, so the campers decide to build a fly, or rain cover, over their tent. The f

ly will be 12 feet high and 16 feet wide. The scouts are building the frame for the fly with two poles slanted and joined together at the top of the tent.
The minimum length of the slanted poles needed to support the fly is
how may feet ????
Mathematics
2 answers:
alisha [4.7K]3 years ago
6 0
The answer is 14.42 feet
Marianna [84]3 years ago
4 0

Answer:

14.42 feet is correct on Plato

Step-by-step explanation:

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What is a force of attraction between an object and the earth due to gravity?
nasty-shy [4]

Newton's law of gravitation says that the force due to gravitation between two objects with masses m₁ and m₁ is given by the formula

F=G\dfrac{m_1m_2}{r^2}

Where r is the distance between the objects, and G is the gravitational constant (about 6.674×10⁻¹¹ m³⋅kg⁻¹⋅s⁻²)

3 0
3 years ago
If CP=Rs. 1200 and loss =10%, find loss amount.​
goldfiish [28.3K]

Answer:

lost 120

Step-by-step explanation:

10% of 1200 is 120 so you subtract 120 from 1200

7 0
3 years ago
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John has 6/8 left after a party. He ate 1/6 of it the next day. How much of the pie is left?
Galina-37 [17]
18/24-4/24=14/24
7/12 will be left
8 0
4 years ago
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Hello! Verify the identity. Please show your work! Use trigonometric identities to verify each expression is equal.
RSB [31]

Answer:

See Below.

Step-by-step explanation:

We want to verify the identity:

\displaystyle \csc^2 x -2\csc x \cot x +\cot ^2 x = \tan^2\left(\frac{x}{2}\right)

Note that the left-hand side is a perfect square trinomial pattern. Namely:

a^2-2ab+b^2=(a-b)^2

If we let <em>a</em> = csc(x) and <em>b</em> = cot(x), we can factor it as such:

\displaystyle (\csc x - \cot x)^2 = \tan^2\left(\frac{x}{2}\right)

Let csc(x) = 1 / sin(x) and cot(x) = cos(x) / sin(x):

\displaystyle \left(\frac{1}{\sin x}-\frac{\cos x }{\sin x}\right)^2=\tan^2\left(\frac{x}{2}\right)

Combine fractions:

\displaystyle \left(\frac{1-\cos x}{\sin x}\right)^2=\tan^2\left(\frac{x}{2}\right)

Square (but do not simplify yet):

\displaystyle \frac{(1-\cos x)^2}{\sin ^2x}=\tan^2\left(\frac{x}{2}\right)

Now, we can make a substitution. Let <em>u</em> = <em>x</em> / 2. So, <em>x</em> = 2<em>u</em>. Substitute:

\displaystyle \frac{(1-\cos 2u)^2}{\sin ^22u}=\tan^2u

Recall that cos(2u) = 1 - sin²(u). Hence:

\displaystyle \frac{(1-(1-2\sin^2u))^2}{\sin ^2 2u}=\tan^2u

Simplify:

\displaystyle \frac{4\sin^4 u}{\sin ^2 2u}=\tan^2 u

Recall that sin(2u) = 2sin(u)cos(u). Hence:

\displaystyle \frac{4\sin^4 u}{(2\sin u\cos u)^2}=\tan^2 u

Square:

\displaystyle \frac{4\sin^4 u}{4\sin^2 u\cos ^2u}=\tan^2 u

Cancel:

\displaystyle \frac{\sin ^2 u}{\cos ^2 u}=\tan ^2 u

Since sin(u) / cos(u) = tan(u):

\displaystyle \left(\frac{\sin u}{\cos u}\right)^2=\tan^2u=\tan^2u

We can substitute <em>u</em> back for <em>x</em> / 2:

\displaystyle \tan^2\left(\frac{x}{2}\right)= \tan^2\left(\frac{x}{2}\right)

Hence proven.

3 0
3 years ago
A triangular prism has a base that is 6 cm by 4 cm and a height of 8 cm. If all dimensions are tripled, what happens to the volu
lana [24]
Im assuming the base of the triangle is 4cm. The volume is 96cm^{3}. 
If the dimensions are tripled, the base is 12, the height is 24, and the length is 18. The volume is  2592cm^{3}, which is 27 times bigger.
If you are increasing each side by a factor of x, you are multiplying the original by x^{3}
3 0
3 years ago
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