Cody was 165cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year.

The sum of 3 consecutive even integers is 78. What is the largest of the integers?

Maksim231197 [3]

Answer:

is the sum 78 or 7,878 (i.e. was there a stutter)?

In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.

Set that to either 78 or 7878, whichever is intended, & solve for n. If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.

No stress! Just logic! Keep the faith!

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Divide 3 by 4, then subtract z from the result

8_murik_8 [283]

Answer:

3/4 = z

Step-by-step explanation:

Step 1: Convert words into an expression

Divide 3 by 4, then subtract z from the result

3/4 - z

Step 2: Solve for z

3/4 - z + z = 0 + z

3/4 = z

Answer: 3/4 = z

7 0

3 years ago

Read 2 more answers

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$