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stiks02 [169]
3 years ago
15

An online clothing company decides to investigate whether offering their customers a coupon upon completion of their first purch

ase will encourage them to make a second purchase. To do so, the company programs the website to randomly select 100 first time customers. Sixty of these customers are randomly selected to receive a coupon for $5 off their next purchase, to be made in the next 30 days. The other 40 customers are not offered a coupon. The table below shows the number of customers in each group that made a second purchase within 30 days of their first purchase.
Based upon the table, is “yes, made a second purchase” independent of “yes, being sent a coupon”?

A) Yes, exactly half of the customers made a second purchase and half did not.
(B) Yes, the largest count in the table comes from those who were sent a coupon and made a second purchase within 30 days.
(C) No, the probability of making a second purchase is not equal to the probability of making a second purchase given that a coupon was sent.
(D) No, the probability of making a second purchase is the same whether or not a coupon was sent.
(E) It is impossible to draw a conclusion about independence because a coupon was not sent to exactly half of the customers.
Mathematics
1 answer:
Mila [183]3 years ago
5 0

Answer:

(C) No, the probability of making a second purchase is not equal to the probability of making a second purchase given that a coupon was sent.

Step-by-step explanation:

Let A = the customer makes a second purchase within 30 days and let B = customer is sent a coupon. Events A and B are independent if P(A) = P(A | B).

P(A) = P(the customer makes a second purchase within 30 days) = \frac{50}{100} = 0.5  

100

50

​  =0.5

P(A | B) = P(the customer makes a second purchase within 30 days | customer is sent a coupon) = \frac{34}{60} = 0.567  

60

34

​  =0.567

Because P(A) ≠ P(A | B) making a second purchase is not independent of being sent a coupon.

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elixir [45]
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
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4 0
3 years ago
Read 2 more answers
Subjects for the next presidential election poll are contacted using telephone numbers in which the last four digits are randoml
vovikov84 [41]

Answer: 0.3439

Step-by-step explanation:

Given :The last four digits for telephone numbers are randomly selected​ (with replacement).

Here , each position can be occupied with any of the digit independently .

Total digits = 10

Total digits other than 0 = 9

For each digits , the probability that it is not 0 = \dfrac{9}{10}=0.9

If we select 4 digits , The probability of getting no 0 =(0.9)^4 =0.6561

(By multiplication rule of independent events)

Now , the probability that for one such phone​ number, the last four digits include at least one 0. = 1- P(none of them is 0)

=1- 0.6561=0.3439

Hence, the probability that for one such phone​ number, the last four digits include at least one 0. is 0.3439 .

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Please answer please
Luda [366]

Answer:

46°

Step-by-step explanation:

Since the 3 sides are given we can use any of the 3 trig. ratios to solve.

Using the tangent ratio in the right triangle

tan ? = \frac{opposie}{adjacent} = \frac{42}{40}, thus

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The product of a number and -7/10 is 1/2 what is the number 1. 7/20 2. -5/7 3. -7/20 4. 5/7
matrenka [14]

Answer:

2)  -5/7

Step-by-step explanation:

\frac{-7n}{10} = \frac{1}{2}

cross-multiply to get:

10 = -14n

-10/14 = n

n = -5/7 (simplified)

3 0
3 years ago
Find the missing side. Round to the nearest tenth.
puteri [66]

Answer:

29.9

Step-by-step explanation:

29.9 rounded to the nearest 10 is 30

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