Russell worked 45.75 hours this week at a rate of $7.86 per hour. what is his gross pay?

Could someone help with this maths answer please

Zielflug [23.3K]

Finding the area would be length x width, but to find the width we'd need to use Area / Length

The area = 44

The Length = 3 and 2/3

Solve

44 ÷ 2 and 2/3 = 12

12 is your answer

6 0

3 years ago

find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2

Alexxandr [17]

The surface is parameterized by

$\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k$

and the normal to the surface is given by the cross product of the partial derivatives of $\vec s$ :

$\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}$

It looks like you're given

$\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}$

Then the normal vector is

$\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k$

Now, the point (2, 2, 0) corresponds to u and v such that

$\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}$

and solving gives $u = v = 1$ , so the normal vector at the point we care about is

$\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k$

Then the equation of the tangent plane is

$\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath + (z-0)\,\vec k\right) = 0$

$-4(x-2) + 2(y-2) - 4z = 0$

$\boxed{2x - y + 2z = 2}$

6 0

2 years ago

What is this percent in simplest form? 15 3/5%=

Paul [167]

Answer:

0.156

Step-by-step explanation:

15 3/5%=(15+ 0.6)/100=15.6/100=0.156

5 0

3 years ago

How many x-intercepts are there in y = –3x2 + 4x + 4

Yakvenalex [24]

Y = -3x^2 + 4x + 4

Educated guess: There may be about 2 x - intercepts in the equation.

7 0

3 years ago

Read 2 more answers

A survey taken in a large statistics class contained the question: "What's the fastest you have driven a car (in miles per hour)

hjlf

Answer:

NO

Step-by-step explanation:

To find out which observation to classify as an outlier, whether the largest or not, a very good approach or way to do this is to apply the 1.5(IQR) rule.

According to the rule, for finding the largest observation in the data that can be classified as an outlier, we would use the formula = Q3 + 1.5(IQR).

Q3 = 120

IQR = Q3 - Q1 = 120 - 95 = 25

Lets's plug these values into Q3 + 1.5(IQR)

We have,

120 + 1.5(25)

= 157.5

Since our max in the observation is given as 155, the largest observation in the data set cannot be set as an outlier because 157.5 which we got from our calculation is higher than the max value we have in the data set.

Our answer is NO.

However, the smallest observation should be set as outlier because:

Q1 - 1.5(IQR) = 95 - (1.5*25) = 57.5, which gives us an outlier that falls within our data range.

3 0

4 years ago