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4 years ago

Can somebody help me please

Mathematics

1 answer:

Firdavs [7]4 years ago

4 0

?????

How can I help you

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Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

Solve for r: d=2r<br> d<br> please hepl me

Luba_88 [7]

R=d/2 is the answer to this

6 0

4 years ago

Read 2 more answers

-(x – 4) + 5 = 3x + 6 – x

slava [35]

Answer:

Step-by-step explanation:

-(x-4)+5=3x+6-x(BODMAS)

-x+4+5=3x+6-x(collect like terms )

4+5=3x+x-x

9=3x (divide both sides by 3)

9/3=3x/3

3=x

4 0

4 years ago

YOU HAVE A GARDEN HOSE AND A 0.5 LITER CONTAINER AND A 0.3 LITER CONTAINER. YOU NEED TO MEASURE OUT 0.1 LITER OF WATER. HOW DO Y

Nikitich [7]

Answer:

Fill up the .3 container and then pour it into the .5

fill up the .3 again and fill up the .5 ... if all is poured in the .5 will overflow over the top.

stop when the .5 is totally full... only .3 will fit... the liquid left in the .3 will be .1

Step-by-step explanation:

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3 years ago

A tree is broken at a height of 9m from the ground and its top touches the ground at distance of 12m from the base of the tree.

KatRina [158]

Answer: i took the test its number 555555

Step-by-step explanation:

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3 years ago