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Leviafan [203]
3 years ago
6

Solve the following, round to 2 decimal places. 36.67 ÷ 12​

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0
So 36.67\12= 3.055833 and the 3 repeats so round up the 5 to get 3.06
Hope I’m correct!
inessss [21]3 years ago
4 0

Answer:

i m the best okay people

Step-by-step explanation:

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How do you solve a system of linear equations by graphing? ​
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This is a self-answering question: you solve it by graphing the equations.

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The equations can be graphed by any of a number of methods. (My favorite is to let a graphing calculator do it.) The method of choice depends on the coefficients and the form the equations are given in. Methods of graphing are a topic for a more lengthy discussion.

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The graph shown compares the rent Andrew and Dave pay for renting bikes from different stores
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An oblique cylinder has a radius of 10 units and slant length of 26 units.
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Step-by-step explanation:

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3 years ago
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Mr. Burrows has cups of flour.
Alexeev081 [22]

The question is incomplete :

However, assume Number of cups of flower 10

Number of flour cups for each pie 1/4

Answer:

8

Step-by-step explanation:

Number of cups of flower = 10

Number of flower cups per crust pie = 1/4 cups

Since, the cups of flower was divided equally into to 5 containers;

Number of flower cups per container :

10 / 5 = 2

Each container has 2 cups of flower each.

1 container was used in making crust pie :

The number of crust pies made is:

Cups of flower in container / cups of flower per crust pie

= 2 ÷ 1/4

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8 0
3 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
kupik [55]

Answer:

(a) 0.873 (b) 0.007 (c) 0.715 (d) 0.277 (e) 1.25 and 1.09

Step-by-step explanation:

The probability that the random variable X takes the value x is given by P(X=x) = 25Cx 0.05^x0.95^{25-x}. Then,

(a) P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})=  0.873

(b) P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007

(c) P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715

(d) P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277  

(e) E(X) = np = (25)(0.05) = 1.25 and Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09

8 0
2 years ago
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