False,
" I am talking about 20-30+ millions lines of code, software at the scale and complexity of Autodesk Maya for example.
If you freeze the development as long as it needs to be, can you actually fix all the bugs until there is simply not a single bug, if such a thing could be verified by computers? What are the arguments for and against the existence of a bug-free system?
Because there is some notion that every fix you make creates more bugs, but I don't think that's true.
By bugs I meant from the simplest typos in the UI, to more serious preventative bugs that has no workaround. For example a particular scripting function calculates normal incorrectly. Also even when there are workarounds, the problem still has to be fixed. So you could say you can do this particular thing manually instead of using the provided function but that function still has to be fixed."
work cited:
https://softwareengineering.stackexchange.com/questions/195571/is-it-possible-to-reach-absolute-zero-bug-state-for-large-scale-software
Answer:
printStars(35);
Explanation:
public class Question {
public static void main(String args[]) {
printStars(35);
}
public static void printStars(int numberOfStars){
for(int i = 1; i <= numberOfStars; i++){
System.out.print("*");
}
System.out.print("\n");
}
}
Answer:Systems analysts
Explanation: System analyst is referred as the person in an organization for resolving the issue related program and information technologies. The person basically design the solution by analyzing the problem accordingly.
Information system of company has any separate department for handling the problems related with the IS-related programs. These problem usually lies under the department of the system analyst. They work on the problem solving, improvement and improvisation, training etc.
The Correct answer would be C. <span>microphone,mouse,scanner
microphone you talk into to give info (data)
a mouse you use to click on objects to give input
a scanner you input a paper/object
hope this helps!! :)
</span>
Answer:
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
Explanation:
Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.
