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bazaltina [42]
2 years ago
10

A(n) is the tool that will help you the most when developing the content you will use in your presentation.

Computers and Technology
1 answer:
ikadub [295]2 years ago
7 0

Answer:

Outline

Hope it helps :)

Explanation:

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These are statements given by witnesses under oath? A. Testimony B. Admissible Evidence C. Indirect Evidence D. Circumstantial E
Aneli [31]

Answer:A. Testimony

Explanation:when someone knows something about what happened in the case held in court or they had witnessed what happened; In order to actual testify on what they know they are called on the stand and they have to raise their hand as a sign to swear an oath before the can give their testimony in court.

8 0
2 years ago
Solve for x<br><br>4d+3/8=-2​
Alexxx [7]

Answer:

-19/32

Explanation:

(If I assume d to be x)

4x+3/8=-2

or,4x=-2-3/8=-19/8

or,x=(-19/8)*(1/4)=-19/32

5 0
2 years ago
Date:<br>Difference between Chemical Equivalent and Electroche-<br>mical equivalent.​
Sergio039 [100]

Answer:

chemical equivalent of an element is the value obtained by dividing the atomic weigh of the given element by valency

5 0
3 years ago
Can someone smart help me
nalin [4]

Answer:

Answer

Explanation:

The only thing that is wrong with this code is the fact that the link is not completed (should be https://[link name].com/)

Other than that the code is fine

7 0
3 years ago
Write a multithreaded program that generates the Fibonacci series using Pthreads thread library. This program should work as fol
Mamont248 [21]

Answer:

#include <pthread.h>

#include <stdio.h>

#include <stdlib.h>

pthread_mutex_t mutex;

int fib[10]; /* this data is shared by the thread(s) */

int in = 0;

void *genFibo(void *param); /* the thread */

int main(int argc, char *argv[])

{

   pthread_attr_t attr;  

   if (argc != 2) {

   fprintf(stderr,"usage: fibthread <integer value>\n");

   return -1;

   }

   int count = atoi(argv[1]);

   if (count < 1) {

   fprintf(stderr,"%d must be>= 1\n", count);

   return -1;

   }

   pthread_attr_init(&attr);

   // Mutex Lock

   pthread_mutex_init(&mutex, NULL);

   // each thread computes fibonacci

   for(int i = 1;i <= count;i++) {

   pthread_t thread;

   pthread_create(&thread, &attr, genFibo, (void*)i);

   pthread_join(thread, NULL);    

   }    

   // print resulting array

   for (int i = 0; i < in;i++) {

   printf("%d ", fib[i]);

   }

   printf("\n");

   pthread_mutex_destroy(&mutex);

}

void *genFibo(void *param)

{

   pthread_mutex_lock(&mutex);

   fib[in++] = fibonacci((int)param);

   pthread_mutex_unlock(&mutex);

   pthread_exit(0);

}

int fibonacci (int x)

{

   if (x <= 1) {

   return 1;

   }

   return fibonacci(x-1) + fibonacci(x-2);

}

4 0
3 years ago
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