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4 years ago

What numbers multiply to 0.32 and also add to 1.2

Mathematics

1 answer:

mylen [45]4 years ago

6 0

.08 x .04 is the right answer

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3. What is the axis of symmetry of the graph of function f(x)=x^2 - 6x - 1

JulijaS [17]

Answer:

Hi! The answer to your question is $X = 3$

Step-by-step explanation:

☆*: .｡.｡.:*☆☆.*: .｡..｡.:*☆☆*: .｡.｡.:*☆☆.*: .｡..｡.:*☆

☁Brainliest is greatly appreciated!☁

<em>Hope this helps!!</em>

<em>- Brooklynn Deka</em>

8 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

4 years ago

Please help! :D Pic is below and dont send links-

julia-pushkina [17]

Answer:

Frogs : 7, 14, 28

Turtles : 3, 6, 12

Step-by-step explanation:

Multiply equivalently with the same multiple.

Equivalent ratios : (7 : 14) (6 : 12)

5 0

3 years ago

Read 2 more answers

There are 1200 students at a school.

const2013 [10]

Answer:

The number of boys that have school dinners is 381.

Step-by-step explanation:

First, we need to find how many students have school dinners:

$SD = 1200*0.62 = 744$

The percent of girls that have school dinners:

$\%SD_{g} = 100\% - 45\% = 55\%$

Now, we need to find the number of boys (b) and girls (g) at a school:

$g = 1200*0.55 = 660$

$b=1200 - 660 = 540$

Hence. the percent of boys that have school dinners is given by:

$SD = g*\%SD_{g} + b*\%SD_{b}$

$\%SD_{b} = \frac{SD - g*\%SD_{g}}{b} = \frac{744 - 660*0.55}{540} = 0.706$

$\%SD_{b} = 70.6\%$

Finally, the number of boys that have school dinners is:

$B = 540*0.706 = 381$

Therefore, the number of boys that have school dinners is 381.

I hope it helps you!

4 0

3 years ago

The average of your first three test grades is 78. what grade must you get on your fourth and final test to make your average 80

Alex73 [517]

You need to score 86

7 0

3 years ago