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boyakko [2]
4 years ago
11

What numbers multiply to 0.32 and also add to 1.2

Mathematics
1 answer:
mylen [45]4 years ago
6 0
.08 x .04 is the right answer

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3. What is the axis of symmetry of the graph of function f(x)=x^2 - 6x - 1
JulijaS [17]

Answer:

Hi! The answer to your question is X = 3

Step-by-step explanation:

☆*: .。.。.:*☆☆.*: .。..。.:*☆☆*: .。.。.:*☆☆.*: .。..。.:*☆

☁Brainliest is greatly appreciated!☁

<em>Hope this helps!!</em>

<em>- Brooklynn Deka</em>

8 0
3 years ago
For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f
butalik [34]

\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k

Let

\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k

The curl is

\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)

where \partial_\xi denotes the partial derivative operator with respect to \xi. Recall that

\vec\imath\times\vec\jmath=\vec k

\vec\jmath\times\vec k=\vec i

\vec k\times\vec\imath=\vec\jmath

and that for any two vectors \vec a and \vec b, \vec a\times\vec b=-\vec b\times\vec a, and \vec a\times\vec a=\vec0.

The cross product reduces to

\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

\nabla\times\vec f=\vec0

which means \vec f is indeed conservative and we can find f.

Integrate both sides of

\dfrac{\partial f}{\partial y}=2xze^{2xyz}

with respect to y and

\implies f(x,y,z)=e^{2xyz}+g(x,z)

Differentiate both sides with respect to x and

\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}

2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}

4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}

\implies g(x,z)=4\sin(xz^2)+h(z)

Now

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)

and differentiating with respect to z gives

\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}

2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}

\dfrac{\mathrm dh}{\mathrm dz}=0

\implies h(z)=C

for some constant C. So

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C

3 0
4 years ago
Please help! :D Pic is below and dont send links-
julia-pushkina [17]

Answer:

Frogs : 7, 14, 28

Turtles : 3, 6, 12

Step-by-step explanation:

Multiply equivalently with the same multiple.

Equivalent ratios : (7 : 14) (6 : 12)

5 0
3 years ago
Read 2 more answers
There are 1200 students at a school.
const2013 [10]

Answer:

The number of boys that have school dinners is 381.  

           

Step-by-step explanation:

First, we need to find how many students have school dinners:

SD = 1200*0.62 = 744

The percent of girls that have school dinners:

\%SD_{g} = 100\% - 45\% = 55\%

Now, we need to find the number of boys (b) and girls (g) at a school:

g = 1200*0.55 = 660

b=1200 - 660 = 540

Hence. the percent of boys that have school dinners is given by:

SD = g*\%SD_{g} + b*\%SD_{b}

\%SD_{b} = \frac{SD - g*\%SD_{g}}{b} = \frac{744 - 660*0.55}{540} = 0.706

\%SD_{b} = 70.6\%

Finally, the number of boys that have school dinners is:

B = 540*0.706 = 381    

Therefore, the number of boys that have school dinners is 381.                                

I hope it helps you!                                                                            

4 0
3 years ago
The average of your first three test grades is 78. what grade must you get on your fourth and final test to make your average 80
Alex73 [517]
You need to score 86
7 0
3 years ago
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