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Likurg_2 [28]
3 years ago
7

(1/2)n+r n - 30. r - 6

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

21

Step-by-step explanation:

1/2*30+6 = 15+6 = 21

Hope I helped

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When analyzing three linear functions, Michele noticed that they all intersected at the point (5, 3). What conclusion can Michel
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Answer: option B. it has the highest y-intercept.

Explanation:

1) point -slope equation of the line

y - y₁ = m (x - x₁)

2) Replace (x₁, y₁) with the point (5,3):

y - 5 = m (x - 3)

3) Expand using distributive property and simplify:

y - 5 = mx - 3m ⇒ y = mx + 5 - 3m

4) Compare with the slope-intercept equation of the line: y = mx + b, where m is the slope and b is the y-intercept

⇒ slope = m

⇒ b = 5 - 3m = y - intercept.

Therefore, for the same point (5,3), the greater m (the slope of the line) the less b (the y-intercept); and the smaller m (the slope) the greater the y - intercept.

Then, the conclusion is: the linear function with the smallest slope has the highest y-intercept (option B).

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3 years ago
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Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

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2 years ago
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