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MArishka [77]
4 years ago
8

How is subtracting polynomials similar to subtracting integers

Mathematics
2 answers:
Oduvanchick [21]4 years ago
8 0

Answer:

When subtracting integers you have to change the sign of the second integer; When subtracting polynomials you have to change the sign of each term in the second polynomia. Then follow rules for addition of integers .

Hope this helps!

IgorLugansk [536]4 years ago
7 0
When you subtract polynomials, it is kind of like subtracting integers, because in both, you subtract normally. For example, 3xy - 2xy = 1xy. You have to subtract integers when you subtract polynomials
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Find the formula for (f + g)(x) and simplify your answer.
Sindrei [870]

(f+g)(x)=3x+\sqrt{x-4}

3 0
3 years ago
Consider the population of four juvenile condors. Their weights in pounds are : 4, 5, 7, 12 (a) Let x be the weight of a juvenil
creativ13 [48]

Answer:

a) 4, 5, 7, 12

b) 7

c) 4.5, 6.5, 8, 6, 8.5, 9.5

d) 7.167              

Step-by-step explanation:

We are given the following in the question:

4, 5, 7, 12

a) unique values for x

4, 5, 7, 12

b) mean of the population

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

\mu =\displaystyle\frac{28}{4} = 7

c) sampling distribution for samples of size 2

Sample size, n = 2

Possible samples of size 2 are (4,5),(4,7),(4,12),(5,7),(5,12),(7,12)

Sample means are:

\bar{x_1} = \dfrac{4+5}{2} = 4.5\\\\\bar{x_2} = \dfrac{4+7}{2} = 6.5\\\\\bar{x_3} = \dfrac{4+12}{2} = 8\\\\\bar{x_4} = \dfrac{5+7}{2} = 6\\\\\bar{x_5} = \dfrac{5+12}{2} = 8.5\\\\\bar{x_6} = \dfrac{7+12}{2} = 9.5

Thus, the list is 4.5, 6.5, 8, 6, 8.5, 9.5

d) mean of the sampling distribution

\bar{x} = \dfrac{4.5 + 6.5 + 8+ 6 + 8.5+ 9.5}{6} = \dfrac{43}{6} = 7.167

6 0
3 years ago
What's the 25th term of 23,16,9,2
Doss [256]

Answer:  –145 is the 25th term in this series where each term is 7 less than the preceding term.

Step-by-step explanation:  Find the difference between the numbers given.

They are decreasing by 7.

The requested term is 25. Subtract -1 . = 24  (n-1)

Multiply 24 × -7 = -168

Add that to to first term

23 + (-168) = the 25th term

–145 is the 25th term in this series where each term is 7 less than the preceding term.

3 0
3 years ago
This is legit due today and I’m nervous that I won’t get done in time. Please help. God bless you.
zlopas [31]

6.

Josef receives 3$ per hour spent doing chores. So, after x hours of chores, he receives 3x dollars. This money must be added to the 10$ he would receive no matter what, so the total expression is

m = 10+3x

7.

We can test the options against the given patterns: in pattern 1, we have one black hexagon and 6 white hexagons. Let's see which equations fit: if we substitute b=1 and w=6 we have:

A) 6 = 6\cdot 1 - ok

B) 6 = 3\cdot 1 +2 - wrong

C) 6 = 2\cdot 1 +4 - ok

D) 6 = 6\cdot 1 + 2 - wrong

E) 6 = 2\cdot 1 + 3 - wrong

So, the only feasible answers are A or C, because all the other functions don't fit even the first pattern. Let's test the two survivors for pattern 2: we have two black hexagons and 8 white hexagons. Plugging b=2 and w=8 into A and C we have

A) 8 = 6\cdot 2 - wrong

C) 8 = 2\cdot 2 +4 - ok

So, the answer is C, because it models correctly pattern 2 as well. For the sake of completeness, let's test this function against pattern 3 as well: we have 3 black and 10 white hexagons. Plugging b=3 and w=10 into C we have

C) 10 = 2\cdot 3 +4 - ok

So, C models correctly all patterns, and thus describe the general rule.

4 0
4 years ago
A random two -digit number (10-99)is drawn find each probability
son4ous [18]

Answer:

Step-by-step explanation:

Given that two digit numbers are used and one digit is drawn randomly.

Sample space = {10,11,...99}

n(S) = 90

32 is only one number favourable

Hence P(32) = 1/90

----------------------------

Odd numbers are exactly 45.

Hence prob (odd number) = 45/90 = 1/2

-------------------------------------

Multiples of 5 are 10,15,.....95

There are exactly 18 numbers.

Hence P(a multiple of 5) = 18/90 =1/5

3 0
3 years ago
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