Is 1/8 greater than 3

To prepare for an upcoming basketball tournament, Coach Somers keeps track of the number of points scored by each player on the

pishuonlain [190]

Answer:

The graph is shown in the picture attached.

Step-by-step explanation:

<u>Defining:</u>

x represents the number of minutes

y represents the number of points scored

<u>Matt scored:</u>

12 points (y) in 20 minutes (x) is shown in the graph as the point (20, 12)

16 points (y) in 28 minutes (x) is shown in the graph as the point (28, 16)

15 points (y) in 24 minutes (x) is shown in the graph as the point (24, 15)

18 points (y) in 25 minutes (x) is shown in the graph as the point (25, 18)

5 0

4 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

4 0

4 years ago

Please help me with question2 someone, thanks

Minchanka [31]

Answer:

Step-by-step explanation:

$\frac{3x-y}{4x+5y}=\frac{3}{5}\\\\$

Cross multiply

5*(3x-y) = 3*(4x + 5y)

5*3x -5*y = 3*4x + 3*5y

15x - 5y = 12x + 15y

15x - 12x = 15y + 5y

3x = 20y

3x = 4y * 5

$\frac{3x}{4y} = 5$

5 0

3 years ago

For a moving object the force acting on the object varies directly from the objects acceleration when a force of 25 N acts on a

77julia77 [94]

Answer:

2m/s²

Step-by-step explanation:

If for a moving object the force acting on the object varies directly from the objects acceleration, then it can be expressed as:

F∝a

F = ka.

F is the force

a is the object's acceleration

From the expression;

k is the constant of proportionality

When an initial force of 25 N acts on the object and the acceleration of the object is 5 m/s², then

k = 25/5

k = 5Ns²/m

If the force exchange to 10 N, the acceleration of the object will be gotten using the relationship above

F = ka

Given F = 10N and k = 5Ns²/m

a = F/k = 10/5

a = 2m/s²

The acceleration of the object will be 2m/s²

3 0

4 years ago

Two of your friends, Matt and Karen, both run to you to settle a dispute. They were working on a math problem, and got different

Anna11 [10]

So in matt's equation, he made a mistake in the a transision from line 2 to line 3
in line 2: -4(-2)2
in line 3: -4(4)
the mistake is that -2 times 2 is not equal +4 it is equal to -4
also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5

so he first subtracted 10 then divided, he should have divided then subtracted
so the equation should have equaled

Karen used the correct (-) times (+) property and the order of operations
so Karen is correct and Matt is wrong.

5 0

3 years ago

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