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swat32
2 years ago
15

the value of x=4 is the solution to all following equation except witch? 2x+7=15 x+5=3x-3 3(x+1)=x+11 or x+12=5x-2

Mathematics
1 answer:
garri49 [273]2 years ago
7 0
Except x+12=5x-2 
because:
4+12= 5*4-2
16=20-2
16=18 -- which is not true 

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I have been on this question for so long if anyone can help me I would greatly appreciate it. Thank you
Phoenix [80]

Answer:

Step-by-step explanation:

let x be the number

2(x+8)=-4x+4

2x+16=-4x+4

6x=-12

x=-2

8 0
2 years ago
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Let f(x)=x^2f ( x ) = x 2. Find the Riemann sum for ff on the interval [0,2][ 0 , 2 ], using 4 subintervals of equal width and t
sladkih [1.3K]

Answer:

A_L=1.75

Step-by-step explanation:

We are given:

f(x)=x^2

interval = [a,b] = [0,2]

Since n = 4 ⇒ \Delta x = \frac{b-a}{n} = \frac{2-0}{4}=\frac{1}{2}

Riemann sum is area under the function given. And it is asked to find Riemann sum for the left endpoint.

A_L= \sum\limits^{n}_{i=1}\Delta xf(x_i) = \frac{1}{2}(0^2+(\frac{1}{2})^2+1^2+(\frac{3}{2})^2)=\frac{7}{4}=1.75

Note:

If it will be asked to find right endpoint too,

A_R=\sum\limits^{n}_{i=1}\Delta xf(x_i) =\frac{1}{2}((\frac{1}{2})^2+1^2+(\frac{3}{2})^2+2^2)=\frac{15}{4}=3.75

The average of left and right endpoint Riemann sums will give approximate result of the area under f(x)=x^2 and it can be compared with the result of integral of the same function in the interval given.

So, (A_R+A_L)/2 = (1.75+3.75)/2=2.25

\int^2_0x^2dx=x^3/3|^2_0=8/3=2.67

Result are close but not same, since one is approximate and one is exact; however, by increasing sample rates (subintervals), closer result to the exact value can be found.

3 0
3 years ago
A rectangle has length (3x-8) and width (2x-7) cm .Write down and simplify an expression for the perimeter of the rectangle. So
tatuchka [14]

Answer:

The perimeter of the rectangle is equal to (10x-30)\ cm

Step-by-step explanation:

Let

L-----> the length of the rectangle

W ----> the width of the rectangle

we know that

The perimeter of rectangle is equal to

P=2(L+W)

we have

L=(3x-8)\ cm\\W=(2x-7)\ cm

substitute

P=2((3x-8)+(2x-7))

P=2(5x-15)

P=(10x-30)\ cm

8 0
3 years ago
Find the absolute maximum and absolute minimum values of tghe function over the indicated interval, and indicate the x-values at
Marina86 [1]

A graph shows ...

... absolute minimum: 5, at x=-1 and x=1

... absolute maximum: 8, at x=2

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2 years ago
What’s 2 to the power of 3
kondaur [170]

Answer:

2.2 can be written 22

Step-by-step explanation:

"Two squared" or "2 to the 2nd power"

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