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leva [86]
3 years ago
14

Find the approximate side length of a square game board with an area of 123 inches to the second power

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0
61.5 or 61 and one half
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What is matrix X if 0.5X=A? Matrix A=[6 -12 4 6].
vladimir1956 [14]

Answer:

See attachment

Step-by-step explanation:

The given matrix equation is:

0.5X = A.

To find Matrix X, we need to multiply both sides of the equation by 2 to obtain:

2 \times 0.5X =2 \times  A

This simplifies to;

X = 2A

By scalar multiplication, we multiply each entry in the matrix A by to 2 to obtain matrix X.

6 0
3 years ago
Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc
siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be x.

So, 54 is equivalent to 36.

Thus, 17 is equivalent to x.

\frac{54}{36} =\frac{17}{x}

By cross multiplying we get:

54x=612

Dividing both sides by 54 we get:

x=11.33\ inches.

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= 54\times 36:17\times 11.33

= 1944:192.61

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

6 0
3 years ago
Read 2 more answers
Find the square root of :<br> √50×8 = ___<br> Please show steps....
Sav [38]
Your answer would be 20.. the square root of 50 is 7.07106781187 x by 8
6 0
3 years ago
Please help I will mark!!
marin [14]

Answer:788

Step-by-step explanation:

6 0
3 years ago
what are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotensue is 15 units long?
givi [52]
Refer to the diagram shown below.

Given:
m∠A = 19°
c = 15

By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835

cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828

Answer:
The lengths are 4.88, 14.18, and 15.00  (nearest hundredth)  

6 0
3 years ago
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