Find the approximate side length of a square game board with an area of 123 inches to the second power

Question 15 of 20

grandymaker [24]

Answer: 3 inches

Step-by-step explanation:

4 0

2 years ago

What is the value of x in the equation below?<br> 12 – 2(x-1)=6

JulijaS [17]

X=25 in this equation. But if u divide by 12 it’s -25

5 0

2 years ago

Read 2 more answers

15 points: can someone help me with this thank you. (all separate equations)

OLga [1]

Step-by-step explanation:

$6x+3y=12\qquad\text{subtract}\ 6x\ \text{from both sides}\\\\6x-6x+3y=12-6x\\\\3y=12-6x\qquad\text{divide both sides by 3}\\\\\dfrac{3y}{3}=\dfrac{12}{3}-\dfrac{6y}{3}\\\\\large\boxed{y=4-2y}\\\\===================$

$2p-k=3\qquad\text{subtract}\ 2p\ \text{from both sides}\\\\2p-2p-k=3-2p\\\\-k=3-2p\qquad\text{change the signs}\\\\k=-3+2p\\\\\large\boxed{k=2p-3}\\\\===================$

$6v-2w=10\qquad\text{subtract}\ 6v\ \text{from both sides}\\\\6v-6v-2w=10\\\\-2w=10-6v\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2w}{-2}=\dfrac{10}{-2}-\dfrac{6v}{-2}\\\\w=-5+3v\\\\\large\boxed{w=3v-5}\\\\===================$

5 0

2 years ago

A tal company has chairs and tables for rent. The total cost to rent 3 chairs and 2 tables is $22. The total cost to rent 5 chai

den301095 [7]

Answer:

$1.5 and $8.75

Step-by-step explanation:

Given data

let tables be x and chairs be y

The total cost to rent 3 chairs and 2 tables is $22

so

3x+2y=22----------1

The total cost to rent 5 chairs and 6 tables is $60

so

5x+6y=60---------2

the system of equation is

3x+2y=22----------1X 6

5x+6y=60---------2X 2

18x+12y= 132

- 10x+12y=120

8x+0y= 12

8x= 12

divide both sides by 8

x= 12/8

x=$1.5

put x= 1.5 in 2

5(1.5)+6y=60---------2

7.5+6y=60

6y=60-7.5

6y=52.5

divide both sides by 6

y= 52.5/6

y=$8.75

7 0

3 years ago

Solve sin x - (3sin x-1) = 0

soldi70 [24.7K]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}$

Step-by-step explanation:

$\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}$

$\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.$

$\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}$

$\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi$

3 0

2 years ago