Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg
Answer:
Both candles will have the same height after 4 hours.
Step-by-step explanation:
The equation for the amount of candle remaining can be given by the following equations:

In which Q(t) is the amount after t hours, Q(0) is the initial amount and a is how much it decreases, in inches, per hour.
Red candle:
8 inches tall and burns at a rate of 7 divided by 10 inch per hour. This means that
. So

Blue candle:
6 inches tall and burns at a rate of 1 divided by 5 inch per hour. This means that
. So

After how many hours will both candles be the same height ?
This is t when


![0.2t - 0.7t = 6 - 8[/yrc][tex]-0.5t = -2](https://tex.z-dn.net/?f=0.2t%20-%200.7t%20%3D%206%20-%208%5B%2Fyrc%5D%3C%2Fp%3E%3Cp%3E%5Btex%5D-0.5t%20%3D%20-2)
Multiplying by (-1)



Both candles will have the same height after 4 hours.
A and b are not true because