Step-by-step explanation:
Question is: how many 84s will fit in 5376? Let's think about some easy multiples:
84 * 100 = 8400, so it's too big
84 * 10 = 840, so it might work
84 | 5376 | 10
-840
84 | 4536 | 10
-840
84 | 3696 | 10
-840
84 | 2856 | 10
-840
84 | 2016 | 10
-840
84 | 1176 | 10
-840
84 | 336
We can't fit any more 840 in 336, so we check how many 84s are in 336 and what's the remainder:
84 | 336 | 4
- 336
So there's no remainder. Now we add all the partial quotients to get the final result:
10 + 10 + 10 + 10 + 10 + 10 + 4 = <u>64
</u>It's correct, I checked it with calculator. I just hope you'll be able to read something from that, it's quite difficult to do partial dividing with no pencil and paper :)
G(x) is an absolute value function. The standard form for an absolute value function is f(x) = |x|.
The slope of this is equal to -6/-4 or 3/2.
It is flipped over the x-axis, so it will have a negative value out front.
g(x) = -3/2|x| is the equation for this graph.
If you calculate SLE to be $25,000 and that there will be one occurrence every four years (ARO), then the ALE is $40,000.
<h3>What is Single-loss expectancy (SLE)?</h3>
A expected monetary decline each moment an asset is at risk is referred to as single-loss expectancy (SLE). It is a term that is most frequently used during risk analysis and attempts to assign a monetary value to each individual threat.
Quantitative risk analysis predicts the likelihood of certain risk outcomes as well as their approximate monetary cost using relevant, verifiable data.
IT professionals must consider a wide range of risks, including the following:
- Errors caused by humans
- Cyber attacks, unauthorised data disclosure, or data misuse are examples of hostile action.
- Errors in application
- System or network failures
- Physical harm caused by fire, natural disasters, or vandalism.
To know more about the Single-loss expectancy (SLE), here
brainly.com/question/14587600
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