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Aliun [14]
3 years ago
11

What is a number increased by 7 is less than 5

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0
X+7< 5 


     a number= x

         increased= +

         by =  7

less than 5 = < 5
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PLEASE HELP!!!
Sholpan [36]

Answer:

You have to replace x for each density

Step-by-step explanation:

Density = Mass / Volumen

1,000 g = 1 kg

1,000,000 cm^3 = 1 m^3

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Using density as x

volumen \:  =  \frac{50000}{x}  \\ volumen  \: sphere \:  = 4\pi {r}^{3}  \\ 4\pi {r}^{3}  =  \frac{50000}{x}  \\ r =  \sqrt[3]{ \frac{50000}{4\pi {x}^{} } }

8 0
3 years ago
3x-7y=2 solve for x. Can you show how you do it?
9966 [12]
1)  3x-7y=2
2)  If you're solving for x, you want to isolate it, so move the -7y to the right:
          3x = 7y + 2
3)  Now, to get x by itself, you divide both sides by 3
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4)  You get:
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8 0
4 years ago
Read 2 more answers
triangle J'K'L' shown on the grid below a dilation of triangle JKL using the origin as the center of dilation:​
-BARSIC- [3]

Answer:  b) 3

<u>Step-by-step explanation:</u>

From K to L the y-length is 2 and the x-length is 1

From K' to L' the y-length is 6 and the x-length is 3

Therefore, J'K'L' is 3 times as large as JKL so the dilation is 3.

6 0
4 years ago
Generate a line up for the 9players on a ball team
Setler79 [48]

Answer:

do a 3 by 3

Step-by-step explanation:

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3 0
3 years ago
Use the table to the right to answer the following question.
zepelin [54]

The energy is compared based on the information given below.

<h3>How to illustrate the energy?</h3>

Energy released by burning 1 kilogram of element A = EA = 5.1 * (10)8

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Therefore,

Ratio = EB / EA = 1.3 * (10)10 / 5.1 * (10)8 = 25

Thus, the fission of 1 kg of element B releases 25 times as much energy as burning 1 kilogram of element A.

Learn more about energy on:

brainly.com/question/13881533

#SPJ1

<u>The other part of the question:</u>

Energy released by burning 1 kilogram of element A = 5.1 times 10 Superscript 8

Energy released by the fission of hydrogen in 1 kilogram of element B = 1.3 times 10 Superscript 10

4 0
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