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Natali5045456 [20]
3 years ago
13

Whole numbers are _integers

Mathematics
2 answers:
Inessa [10]3 years ago
5 0

Answer:

Step-by-step explanation

:

Whole numbers are positive integers

antoniya [11.8K]3 years ago
4 0

Hello There! Whole numbers are "ALWAYS" Integers

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What is the value of n in the equation 1/2(n-4)-3=3-(2n+3) ?
bulgar [2K]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
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2x+y=3<br>-x + 3y = -12​
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Use Photomath it’s amazing
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A bus has 15 passengers. At the first stop, 5 passengers board the bus and 2 passengers get off the bus. At the second stop, 3 p
andrezito [222]
Stop 1 : -

15 + 5 = 20

20 - 2 = 18

So, on the first stop 18 passengers were left on the bus going to the next stop.

Stop 2 : - 

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8 0
3 years ago
Given m∥n, find the value of x and y.
kupik [55]
X=2
y=149
————-
Solve 8x+15=7x+17
alternate angles are equal
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3 0
2 years ago
A polynomial with rational coefficients has roots 5 and -6i. (The i is an imaginary number not variable). What is the polynomial
mars1129 [50]

Answer:

<em>The answer is</em>  <em>{x^{3}-(5)x^{2} (36)× x-(180)</em>

Step-by-step explanation:

   A polynomial with rational coefficients has roots 5 and -6i (There i is the    

   imaginary number not variable )

   As we knew that imaginary no comes in pair . This means that if  -6i is

   one root then the other root will be 6i

   So if we assume the lowest polynomial that is possible is given as

    {x^{3}-(sum of all roots)x^{2} +(roots taken two at a time)

    x-(product of all roots)

    {x^{3}-(5+6i+(-6i))x^{2} +(5×6i +5×(-6i) +6i×(-6i))

    x-(5×6i×(-6i))

    i^2 = -1

    <em>{x^{3}-(5)x^{2} (36)× x-(180)</em>

<em>    </em>The <u>general case</u> we assume that the three previous roots and rest roots

   a4,a5,a6 ...............an

  x^n-(sum of all roots)×x^{n-1} +(roots taken two at a  

   time) ×x^{n-2}- .......................................... (product of all roots)

3 0
3 years ago
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