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dimaraw [331]
3 years ago
12

The fill weight of a certain brand of adult cereal is normally distributed with a mean of 910 grams and a standard deviation of

5 grams. We calculated the value of z for a specific box of this brand of cereal and the z value was negative. This negative z value indicates that
A.We made a mistake in our calculations, as z must always be a nonnegative number.
B. The fill weight exceeds 910 grams.
C. The fill weight is less than 910 grams.
D. The fill weight is equal to 910 grams
Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

C. The fill weight is less than 910 grams.

Step-by-step explanation:

To normalize a given stadistical we do:

\frac{X - \mu }{\sigma} \\Where:\\X = $ the weight of the cereal box\\\mu = $ the mean of 910 grams\\\sigma = $ the standard deviation

To be negative then, X should be lower than the mean.

Therefore, is the nevatige value of Z represent the value is below the mean therefore, below 910 gram

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3 years ago
I really need Help with this equation Please!!!!
Slav-nsk [51]

Answer:

Option D:  - 6;  $ \textbf{-5}\frac{\textbf{5}}{\textbf{2}} $;   $ \textbf{-4}\frac{\textbf{1}}{\textbf{5}} $.

Step-by-step explanation:

The sequence is defined by:

$ A(n) = -6 + (n - 1)\bigg( \frac{1}{5} \bigg ) $

To find the first term of the sequence simply substitute n = 1.

First term of the sequence:

$ A(1) = -6 + (1 - 1)\bigg( \frac{1}{5} \bigg ) $

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Fourth term of the sequence:

$ A(2) = -6 + (4 - 1) \bigg ( \frac{1}{5} \bigg) $

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        $ = \frac{-25 - 2}{5} $

        $ = - 5 - \frac{2}{5} $

        $ = -5\frac{2}{5} $   is the required answer.

Tenth term of the sequence:

$ A(10) = - 6 + (10 - 1) \bigg( \frac{1}{5} \bigg) $

         $ = - 6 + 9\bigg( \frac{1}{5} \bigg) $

         $ = \frac{-30 + 9}{5} $

         $ = \frac{-21}{5} $

         $ = \frac{-20 - 1}{5} $

         $ = - 4 - \frac{1}{5} $

         $ = -4\frac{1}{5} $  is the required answer.

       

       

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