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Marianna [84]
3 years ago
9

What is the area of parallelogram ABCD? ____ square units

Mathematics
1 answer:
valentinak56 [21]3 years ago
6 0

Answer:

13

Step-by-step explanation:

Here's a method of finding the area of any polygon knowing its vertices. I'm using this parallelogram as an example.

Make a table like this (each vertex with its x- and y-coordinates):

Pt    x       y

A     3      6

B     6      5

C     5      1

D     2      2

A     3      6

Now multiply each x-coordinate by the y-coordinate on the line below and write it on the right side. Bold type shows the first multiplication.

       x       y

A     3      6

B     6      5      15

C     5      1        6

D     2      2      10

A     3      6      12

Now multiply each y-coordinate by the x-coordinate on the line below and subtract from each produce you already have. Do each subtraction. Bold type shows the first multiplication.

       x       y

A     3     6

B     6      5      15 - 36 = -21

C     5      1        6 - 25 = -19

D     2      2      10 - 2 =     8

A     3      6      12 - 6 =     6

Add all the differences.

       x       y

A     3      6

B     6      5      15 - 36 = -21

C     5      1        6 - 25 = -19

D     2      2      10 - 2 =     8

A     3      6      12 - 6 =     6

                                   +____

                                       -26

The area of the polygon is the absolute value of half of the sum of the differences.

area = |-26/2| = |-13| = 13

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Step-by-step explanation:

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Step-by-step explanation:


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Which equation is represented by the table?
MatroZZZ [7]

Answer:

y=-|x-3|-3

Step-by-step explanation:

The table shows values of y for different values of x.

Let us test each equation with the values given in the table.

Equation 1: y=|x+3|-3

For x = 1, we get,

y=|x+3|-3=|1+3|-3=|4|-3=4-3=1

So, we got 1 for y. But as per table, value of y should be -5.

So, equation 1 is incorrect.

Equation 2: y=-|x-3|-3

For x = 1, we get,

y=-|x-3|-3=-|1-3|-3=-|-2|-3=-(2)-3=-5

So, we got -5 for y. It matches with the value of table.

Let us check for another value of x in order to confirm.

For x =2, we get,

y=-|x-3|-3=-|2-3|-3=-|-1|-3=-(1)-3=-4

So, we got -4 for y. It matches with the value of table.

So, equation 2 is the correct answer.

We can be completely sure by checking the remaining equations too.

Equation 3: y=|x-3|-3

For x = 1, we get,

y=|x-3|-3=|1-3|-3=|-2|-3=2-3=-1

So, we got -1 for y. But as per table, value of y should be -5.

So, equation 3 is incorrect.

Equation 4: y=-|x+3|-3

For x = 1, we get,

y=-|x+3|-3=-|1+3|-3=-|4|-3=-4-3=-7

So, we got -7 for y. But as per table, value of y should be -5.

So, equation 4 is incorrect.

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