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3 years ago

What is the area of parallelogram ABCD? ____ square units

Mathematics

1 answer:

valentinak56 [21]3 years ago

6 0

Answer:

Step-by-step explanation:

Here's a method of finding the area of any polygon knowing its vertices. I'm using this parallelogram as an example.

Make a table like this (each vertex with its x- and y-coordinates):

Pt x y

A 3 6

B 6 5

C 5 1

D 2 2

A 3 6

Now multiply each x-coordinate by the y-coordinate on the line below and write it on the right side. Bold type shows the first multiplication.

x y

A 3 6

B 6 5 15

C 5 1 6

D 2 2 10

A 3 6 12

Now multiply each y-coordinate by the x-coordinate on the line below and subtract from each produce you already have. Do each subtraction. Bold type shows the first multiplication.

x y

A 3 6

B 6 5 15 - 36 = -21

C 5 1 6 - 25 = -19

D 2 2 10 - 2 = 8

A 3 6 12 - 6 = 6

Add all the differences.

x y

A 3 6

B 6 5 15 - 36 = -21

C 5 1 6 - 25 = -19

D 2 2 10 - 2 = 8

A 3 6 12 - 6 = 6

+____

-26

The area of the polygon is the absolute value of half of the sum of the differences.

area = |-26/2| = |-13| = 13

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Identify the correct solution for<br> 3/6 x 5.

Setler79 [48]

Answer:

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3 years ago

According to the MIT Airline Data Project, American Airlines controlled 15.5% of the domestic market during a recent year. A ran

Naya [18.7K]

Answer:

0.0143

Step-by-step explanation:

In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.

We proceed as follows;

The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155

Let’s call this probability p

The probability that he/she isn’t on the flight, let’s call this q

q =1 - p= 0.845

Sample size, n = 155

P(X < A) = P(Z < (A - mean)/standard deviation)

Mean = np

= 125 x 0.155

= 19.375

Standard deviation = √npq

= √ (125 x 0.155x 0.845)

= 4.0462

P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)

= P(Z < (10.5 - 19.375)/4.0462)

= P(Z < -2.19)

= 0.0143

4 0

3 years ago

Read 2 more answers

I need help with this please

Savatey [412]

Answer:

t = $\frac{D-M}{Mr}$

Step-by-step explanation:

Given

D = M + Mrt ( subtract M from both sides )

D - M = Mrt ( divide both sides by Mr )

$\frac{D-M}{Mr}$ = t

7 0

3 years ago

Read 2 more answers

CDEF is a parallelogram. Solve for x.

Lana71 [14]

Answer:

x = 12

Step-by-step explanation:

24 = 3x - 12 (opposite sides of a parallelogram are equal)

24 + 12 = 3x

36 = 3x

36/3 = x

12 = x

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3 years ago

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he one‑sample t statistic from a sample of n = 23 observations for the two‑sided test of H 0 : μ = 15 versus H α : μ > 15 has

DedPeter [7]

Answer:

$t = 2.24$

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

Step-by-step explanation:

Data given and notation

$\bar X$ represent the mean height for the sample

$s$ represent the sample standard deviation

$n=23$ sample size

$\mu_o =15$ represent the value that we want to test

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

For this case the statistic is given:

$t = 2.24$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

5 0

3 years ago