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Galina-37 [17]
3 years ago
10

An increased the quantities of all the ingredients in a recipe by 60, percent. She used 80 grams left parenthesis, right parenth

esis of cheese. How much cheese did the recipe require?
Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

The recipe did require 50 grams of cheese.

Step-by-step explanation:

Since, 60 percent extra cheese is used, therefore the given amount of cheese is 160% of recipe requirement. Or in other words, the given amount of cheese is 1.6 times the requirement.

80 grams = (1.6)(Recipe Requirement)

Recipe Requirement = 80/1.6 grams

<u>Recipe Requirement = 50 grams</u>

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VMariaS [17]

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-10

Step-by-step explanation:

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3 years ago
Pumps a, b, and c operate at their respective constant rates. pumps a and b, operating simultaneously, can fill a certain tank i
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Let a, b, and c be the times each pump will fill the tank when working alone.

Therefore, in 1 hour;

1/a +1/b = 1/(6/5) = 5/6 ---- (1)
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1/b+1/c = 1/(2) = 1/2 ---- (3)

From equation (1)
1/a = 5/6-1/b

Substituting for 1/a in eqn (2)
5/6-1/b+1/c = 2/3
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Using eqn (4) in eqn (3)
1/b+1/b-1/6 = 1/2
2/b-1/6 = 1/2
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This means, in 1 hour and with all the pumps working together, the tank will be filled to;
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15. What polynomial must be added to .x^2-2x+ 6 so that<br> the sum is 3x^2+ 7x ?
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Step-by-step explanation:

Just subtract the two because x + y = z and z-x = y

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You can test this by adding this expression back to the original.

x^2-2x+6+(2x^2+9x-6) = 3x^2+7x

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