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Find the value of the trigonometric function to find an approximate value correct to give decimal places

liq [111]

If you have a graphing calculator set it to radian mode and put these in there.

6 0

3 years ago

What is the slope of ( 6 , − 6 and ( − 18 , 3 )

jenyasd209 [6]

Answer:

The slope is -3/8

Step-by-step explanation:

(6,−6);(−18,3)

(x1,y1)=(6,−6)

(x2,y2)=(−18,3)

Use the slope formula:

m= y2−y1 /x2−x1

3−−6 /−18−6

9 /−24

−3 /8

6 0

3 years ago

Read 2 more answers

Gina made 9350ml chicken noodle soup she packed 1.8l of soup in her kids lunches she froze the rest of the soup how many ml of s

Andre45 [30]

Answer:

7550 ml of soup Gina have left to freeze.

Step-by-step explanation:

Given:

Gina made 9350ml chicken noodle soup, she packed 1.8l of soup in her kids lunches.

She froze the rest of the soup.

Now, to find the ml of soup Gina have left to freeze.

The total quantity of soup Gina made = 9350 ml.

Quantity she packed for lunches = 1.8 l.

Now, we convert l into ml by using conversion factor:

1 l = 1000 ml.

1.8 l = 1.8 × 1000 ml.

1.8 l = 1800 ml.

Thus, the quantity she packed for lunches = 1800 ml.

Now, to get the ml of soup Gina have left to freeze we subtract the quantity she packed for lunches from the total quantity of soup she made:

$9350\ ml-1800\ ml\\\\=7550\ ml.$

Therefore, 7550 ml of soup Gina have left to freeze.

6 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

3 years ago

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand

lbvjy [14]

Answer:

a) 0.8708 = 87.08% probability that x is less than 60

b) 0.9641 = 96.41% probability that x is greater than 16.

c) 0.8349 = 83.49% probability that x is between 16 and 60

d) 0.1292 = 12.92% probability that x is more than 60.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 43, \sigma = 15$

a. x is less than 60

This is the pvalue of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 43}{15}$

$Z = 1.13$

$Z = 1.13$ has a pvalue of 0.8708

0.8708 = 87.08% probability that x is less than 60

b. x is greater than 16

This is 1 subtracted by the pvalue of Z when X = 16. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16 - 43}{15}$

$Z = -1.8$

$Z = -1.8$ has a pvalue of 0.0359

1 - 0.0359 = 0.9641

0.9641 = 96.41% probability that x is greater than 16.

c. x is between 16 and 60

This is the pvalue of Z when X = 60 subtracted by the pvalue of Z when X = 16. We found those in a and b, si:

0.8708 - 0.0359 = 0.8349

0.8349 = 83.49% probability that x is between 16 and 60

d. x is more than 60

This is 1 subtracted by the pvalue of Z when X = 60.

So

1 - 0.8708 = 0.1292

0.1292 = 12.92% probability that x is more than 60.

6 0

3 years ago