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3 years ago

How many quarts does it take to fill a kitchen sink

1 answer:

3 0

The average kitchen sink has a width of approximately 23.5 inches, a length of approximately 31.5 inches, and a depth of approximately 21 inches.

Multiplying these values together, we can see that the volume of the average kitchen sink is about 15545.25 cubic inches.

The conversion of cubic inches to liquid gallons is 1 cubic inch = approximately 0.004329 gallons.

Multiplying these numbers, we can see that 15545.25 cubic inches is the same as approximately 67.29538725 gallons. Now, we just have to multiply that number by 4, since there are 4 quarts in a gallon.

67.29538725 * 4 = 269.181549

It takes approximately 269.181549 quarts to fill the average kitchen sink.
Hope that helped =)

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Solve: 6x + 10 = 4x -8. Determine how many solutions? (exactly one, infinitely many, no solution)

Vesnalui [34]

Answer:

x = - 9

Step-by-step explanation:

6x + 10 = 4x - 8

6x - 4x = - 10 - 8

2x = - 18

x = - 18 : 2

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3 years ago

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Step-by-step explanation:

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2 years ago

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2 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
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Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

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Mademuasel [1]

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Step-by-step explanation:

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