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Zina [86]
3 years ago
14

Four ninths plus one ninth

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Answer:

5/9

Step-by-step explanation:

SIZIF [17.4K]3 years ago
7 0

Answer:

5/9

Step-by-step explanation:

4/9 + 1/9

To add fractions, you need a common denominator. You already have a common denominator of 9, so just add the numerators.

4/9 + 1/9 = 5/9

Since there is no common factor of 5 and 9 other than 1, the fraction is already reduced.

Answer: 5/9

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Help fast please :) :) :) :) :)
zavuch27 [327]
Yeah I’m also not %100 but I agree with the first person, #3
7 0
3 years ago
Which point on the graph shows the price of 6 ounces of cheese? Use the formula y=x÷2 to find y when x is 6.
RSB [31]

The value of y is 3 when x is 6.

Solution:

The given table is the amount of cheese in ounces and the cost price.

Let x represents the amount of cheese and y represents the cost price.

The formula which derived from the table is y = x ÷ 2.

That is $y=\frac{x}{2}.

<u>To find the value of y when x is 6:</u>

$y=\frac{x}{2}

Substitute x = 6 in the formula, we get

$y=\frac{6}{2}

y = 3

Hence the value of y is 3 when x is 6.

7 0
3 years ago
A parallelogram with an equal base and height and an area grater than 64 square meters
Sophie [7]
Idk I just need to answer some more questions
5 0
3 years ago
Quotient + remainder <br> I need help I would have 20 points
nexus9112 [7]

We want to compute

\dfrac{-5x^4+4x^3-20x^2+15x-16}{-x^2-3}

The goal is to write it in the following form:

-5x^4+4x^3-20x^2+15x-16=Q(x)(-x^2-3)+R(x)

First step: How many "copies" of -x^2 does -5x^4 contain? We can write -5x^4=(-x^2)(5x^2), so the answer is 5x^2 copies.

If we distribute 5x^2 to -x^2-3, we get

5x^2(-x^2-3)=-5x^4-15x^2

If we were done, then this product would have matched the numerator at the start. But it doesn't; there are still some terms that need to vanish. In particular, we still have to account for

(-5x^4+4x^3-20x^2+15x-16)-(-5x^4-15x^2)=4x^3-5x^2+15x-16

Second step: How many copies of -x^2 can we find in 4x^3? Well, 4x^3=(-4x)(-x^2), so the answer is -4x. Then

(5x^2-4x)(-x^2-3)=-5x^4+4x^3-15x^2+12x

but this still doesn't match the original numerator. We still have to deal with

(-5x^4+4x^3-20x^2+15x-16)-(5x^2-4x)(-x^2-3)=-5x^2+3x-16

Third step: How many copies of -x^2 can we get out of -5x^2? -5x^2=5(-x^2). Then

(5x^2-4x+5)(-x^2-3)=-5x^4+4x^3-20x^2+12x-15

This also doesn't match the original numerator. We have a difference between what we have and what we want of

(-5x^4+4x^3-20x^2+15x-16)-(5x^2-4x+5)(-x^2-3)=3x-1

But we also can't divide 3x into chunks of -x^2, and we can't continue the division algorithm.

Our final answer would be

\dfrac{-5x^4+4x^3-20x^2+15x-16}{-x^2-3}=5x^2-4x+5+\dfrac{3x-1}{-x^2-3}

For the second problem, you should find

\dfrac{-15x^3-13x+4}{5x^2+2}=-3x+\dfrac{-7x+4}{5x^2+2}

4 0
3 years ago
If f and g are continuous functions with f(3)=5 and lim x--&gt;3 [2f(x)-g(x)]= 4, find g(3)
Ierofanga [76]
Because f,g are continuous,

\displaystyle\lim_{x\to3}(2f(x)-g(x))=2\lim_{x\to3}f(x)-\lim_{x\to3}g(x)=2f(3)-g(3)=4
10-g(3)=4
g(3)=6
6 0
3 years ago
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