Resources will become scarce, and competition will rise. This can present in physical, political, or social ways. Once the population crosses the balancing point beyond carrying capacity, a number of things can happen that "correct" the problem, including out migration, starvation, disease, and conflict. Often more than one of things happens at the same time.
Dense connective tissue, also called dense fibrous tissue, is a type of connective tissue with fibers as its main matrix element. ... Dense connective tissue forms strong, rope-like structures such as tendons and ligaments. Tendons attach skeletal muscles to bones; ligaments connect bones to bones at joints. I hope this helps
Answer:
5 lumbar vertebrae
Explanation:
As you can see in the image I annexed, a typical adult skeleton has 5 lumbar vertebrae (colored in red), they are cylindrical bones located between the rib cage and the pelvis, they are the largest segments of the vertebral column. These vertebrae carry all of the upper body’s weight, they protect the spinal cord and nerves in the vertebral canal, they also provide flexibility and movement to the trunk region.
I hope you find this information useful and interesting! Good luck!
Answer: In On the Origin of Species, Darwin claimed that there was a continual 'struggle for existence' in nature, in which only the fittest would survive. This theory came partly from his reading of Thomas Malthus's Essay on the Principle of Population.
Answer:
5.) The possible genotypes should be: RR RB BB ( if the could for the same proteins)
6.) Frequency of R: 0.5
7.)Frequency of R: 0.5
8.)Frequency of R: 0.375
Explanation:
5.) If R and B code for the different forms of the same protein then they are only a few possible out comes
6.) First calculate the total alleles in population
allele R= 40
Allele B=40
total allele = R+B= 40+40
=80
Now to find allele R frequency is:
(Total R alleles) / (Total allele in pop)
40/80=
0.5
7.)Calculate the total alleles
Alleles from for R
RR= 10
R=10x 2= 20
Multiply the value by 2 because there are 2 R alleles present in
RB=20
R=20
Number doesn't change there is only 1 R allele
Total R=20+20
=40
Alleles For B
BB=10
B=10×2
=20
Same thing here, two B alleles together so multiple by 2
RB=20
B=20
Total B= 20+20
=40
Total alleles in pop add
40+40
=80
Frequency of R
Total of R/Total Alleles
=40/80
=0.5
8.)Repeat the same thing in 7 but use different numbers
RR=10
R=10x2
=20
RB=10
R=10
Total R= 20+10
=30
