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garri49 [273]
3 years ago
9

Angraecoid orchids provide nectar to the African moths. The moths in turn help in pollinating the plant. What type of evolution

do these two
species follow?
A
B
C
D.
coevolution
adaptive evolution
convergent evolution
reproductive isolation
Biology
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

A. Coevolution

Explanation:

Coevolution occurs when two species/organisms reciprocally affect the evolution of one another. An example is the coevolution is flowering plants and associated pollinators (e.g., bees, birds, and other insect species). Moths benefit form nectar and orchids benefit from pollinaton.

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Very large premolar and molar teeth, a sagittal crest, heavy mandibles, and wide zygomatic arches are found in modern gorillas,
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Answer:

The correct answer will be option- Australopithecus.

Explanation:

<em>Australopithecus</em> is an extinct genus of a large group of animals called primates. This genus is closely related to humans which may or may not be ancestors of <em>Homo sapiens</em>.

Australopithecus exhibits traits of both ape and human-like which is distinguished by the small size of the brain, smaller canine teeth but large molar and premolar teeth, broad dish-shaped face, sagittal crest, large molar teeth, flared zygomatic arches and sloping forehead.

Thus, option- Australopithecus is the correct answer.

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When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red
Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

  • RR- red
  • ww - white
  • Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

<u>From this cross the expected ratios are:</u>

  • 1/4 RR (red)
  • 2/4 Rw (pink)
  • 1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3><u>Chi square test</u></h3>

X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}

<u>The observed frequencies were:</u>

  • 34 Red
  • 76 Pink
  • 40 White

Total 150

<u>The expected frequencies for our null hypothesis are:</u>

  • 1/4 x 150 = 37.5 Red
  • 2/4 x 150 = 75 Pink
  • 1/4 x 150 = 37.5 white

X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}

X^2=0.5067

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

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