10. 6 ten dollar bills and 1 five dollar bill
Answer:
3rd option
Step-by-step explanation:
8x³ - 27y³ ← is a difference of cubes and factors in general as
a³ - b³ = (a - b)(a² + ab + b²)
8x³ - 27y³
= (2x)³ - (3y)³
= (2x - 3y)((2x)² + 2x(3y) + (3y)²) , that is
= (2x - 3y)(4x² + 6xy + 9y²)
Hello!
You subtract the amount of flour you started with by the amount you used
2.250 - 0.725 = 1.525
The answer is 1.525 kilograms
Hope this helps!
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213