True or false please help

PLEASE HELP QUICKLY

andreev551 [17]

Answer:

He ran one mile in 20 minutes

Step-by-step explanation:

4 0

3 years ago

The following are the ages (years) of 5 people in a room:

slava [35]

Answer:

The age of the person who entered the room is 15

Step-by-step explanation:

We are given:

Ages of 5 people in a room are:

17, 16, 15, 17, 22

A person enters room, and then the mean age of 6 people is 17.

We need to find the age of person who entered the room.

The formula to calculate mean is: $Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}$

Now, in question we are given mean of 6 people that is 17

The age of 5 people are given while age of one person who enters the room is unknown.

Let age of person whose age is unknown= x

Now finding x using mean formula

$Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}\\17=\frac{17+16+ 15+ 17+ 22+x}{6}\\17=\frac{87+x}{6}\\17*6=87+x\\102=87+x\\x=102-87\\x=15$

So, The value of x: x=15

Hence, the age of the person who entered the room is 15

4 0

3 years ago

Select all values of x that make the inequality true -x+6> 10 true .

Rufina [12.5K]

Answer:

C. -4.01

H. -7

Step-by-step explanation:

Solving inequalities:

We have a set of numbers to verify which ones of them make the below inequality true

$-x+6>10$

Rearrange

$-10+6>x$

Operating

$-4>x$

Flipping

$x$

The set of solutions contains every number less than -4

There are only two numbers less than -4 in the set of options:

C. -4.01

H. -7

4 0

3 years ago

Read 2 more answers

Assume V and W are finite-dimensional vector spaces and T is a linear transformation from V to W, T: Upper V right arrow Upper

scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.

8 0

3 years ago

Which story problem could be solved using the given equation? 1/5×2/3=m

Ksju [112]

its b. hope this helps i guess

5 0

4 years ago

Read 2 more answers