All categories

3 years ago

True or false please help

Mathematics

2 answers:

Ray Of Light [21]3 years ago

4 0

Answer:

false

Step-by-step explanation:

NeX [460]3 years ago

3 0

Answer:

true

Step-by-step explanation:

You might be interested in

What is the value of g(3) when g(2) = 21–2?

Evgen [1.6K]

Answer:

g(3)=31.5-3

Step-by-step explanation:

first you want to find g(1) or g(x). all you have to do for this is divide every number by two, since 2/2 is 1.

g(1)=10.5-1

now to find g(30 you just multiply it all by 3.

g(3)=(10.5-1)*3

g(3)=31.5-3.

5 0

3 years ago

What are two numbers that have a sum of 77.95 and a diffrence of 30.61

lianna [129]

The answer to your question is 54.28 and 23.67.

6 0

3 years ago

The mean number of automobiles entering a mountain tunnel per two-minute period is one. An excessive number of cars entering the

viva [34]

Answer:

A Poisson model seems reasonable for this problem, since we have the mean during the time interval.

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x)=\frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The mean number of automobiles entering a mountain tunnel per two-minute period is one.

This means that $\mu = 1$ .

For a Poisson model to be reasonable, we only need the mean during the time interval. So yes, a Poisson model seems reasonable for this problem.

Find the probability that the number of autos entering the tunnel during a two-minute period exceeds three.

We want to find $P(X>3)$

Either this number is less or equal to 3, or it exceeds 3. The sum of the probabilities is decimal 1. So:

$P(X \leq 3) + P(X > 3) = 1$

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1}*1^{0}}{(0)!} = 0.3679$

$P(X = 1) = \frac{e^{-1}*1^{1}}{(1)!} = 0.3679$

$P(X = 2) = \frac{e^{-1}*1^{2}}{(2)!} = 0.1839$

$P(X = 3) = \frac{e^{-1}*1^{3}}{(3)!} = 0.0613$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3679 + 0.3679 + 0.1839 + 0.0613 = 0.981$

Finally

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.981 = 0.019$

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

8 0

3 years ago

Please help! <br> Does these set of numbers form a Pythagorean triple? Explain. <br><br> 8,6,9

Nataly [62]

Answer:

Step-by-step explanation

3,6,9

3 0

3 years ago

Part A: Sam rented a boat at $225 for 2 days. If he rents the same boat for 5 days, he has to pay a total rent of $480.

klemol [59]

Answer:

y = 85x + 55

Step-by-step explanation:

If we use the given prices as coordinates we will get the coordinates (2, 225) and (5, 480) and if we use the rise over run which in this case is 255/3 then we get the slope which is $85 and now we plug what we know into y = mx + b. we now have the equation 225 = (85)2 + b which can be simplified to 55 = b and now we can create the equation y = 85x + 55.

Hope this helps and please mark brainliest :)

4 0

3 years ago