My question is 4318 divided by 7 please tell me

Mathematics

2 answers:

Ivahew [28]2 years ago

8 0

4318/7
= 616 (r= 6)

The final answer is 616 (r=6)~

Vikki [24]2 years ago

5 0

1.You should set up the long division.


2 Calculate 43 ÷ 7, which is 6 with a remainder of 1.


3 Bring down 1, so that 11 is large enough to be divided by 7.


4 Calculate 11 ÷ 7, which is 1 with a remainder of 4.

5 Bring down 8, so that 48 is large enough to be divided by 7.


6 Calculate 48 ÷ 7, which is 6 with a remainder of 6.


7 Therefore, 4318 ÷ 7 = 616 with a remainder of 6.

616 with a remainder of 6 or 616.8571

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An irregular parallelogram rotates 360° about the midpoint of its diagonal. How many times does the image of the parallelogram c

Ad libitum [116K]

Answer:

The correct options is A.

Step-by-step explanation:

The each diagonal of an irregular parallelogram divides the parallelogram in two equal and congruent parts. The diagonal bisects each other.

It means, if a irregular parallelogram rotates 180° about the midpoint of its diagonal, then the image of the parallelogram coincide with its preimage during the rotation.

If a irregular parallelogram rotates 360° about the midpoint of its diagonal, then the image of the parallelogram coincide 2 times with its preimage during the rotation.

Therefore the correct option is A.

6 0

2 years ago

Which expression is equivalent to logbase12 ((1/2)/8w)?

Lunna [17]

$\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of rationals} \\\\ log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_{12}\left( \cfrac{~~\frac{1}{2}~~}{8w} \right)\implies \begin{array}{llll} \log_{12}\left( \frac{1}{2} \right)&-&\log_{12}(8w)\\\\ \log_{12}(1)-\log_{12}(2)&-&[\log_{12}(8)+\log_{12}(w)] \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \log_{12}(1)-\log_{12}(2)-\log_{12}(8)-\log_{12}(w)~\hfill$