Answer:
1) ΔACD is a right triangle at C
=> sin 32° = AC/15
⇔ AC = sin 32°.15 ≈ 7.9 (cm)
2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:
AB² = AC² + BC²
⇔ AB² = 7.9² + 9.7² = 156.5
⇒ AB = 12.5 (cm)
3) ΔABC is a right triangle at C
=> sin ∠BAC = BC/AB
⇔ sin ∠BAC = 9.7/12.5 = 0.776
⇒ ∠BAC ≈ 50.9°
4) ΔACD is a right triangle at C
=> cos 32° = CD/15
⇔ CD = cos32°.15
⇒ CD ≈ 12.72 (cm)
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
K=1/3=10
L=1/5=6
10+6=16
30-16=14
Answer: The last one
Step-by-step explanation: The data is all between 4 and 7 and there are no gaps. The max is 7 dollars as stated.
12 girls out of 30 were selected, so the ratio "selected:tried" if 12/30. This fraction can be simplified into
Similarly, 16 boys out of 40 were selected, so the ratio "selected:tried" if 16/40. This fraction can be simplified into
So yes, the ratio of the number of students on the team to the number of students trying out the same for both boys and girls
Answer:
C. 2^(4 + 6) = 2^10.
Step-by-step explanation:
8^2 = (2^3)^2
= 2^6.
So 2^4 * 8^2
= 2^4 * 2^6
= 2^(4+6).
