Answer:
yes.<em> </em><em>2</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>only</em><em> </em><em>even</em><em> </em><em>prime</em><em> </em><em>number</em><em>. </em>
Step-by-step explanation:
<em>Prime</em><em> </em><em>number</em><em> </em><em>means</em><em> </em><em>a</em><em> </em><em>number</em><em> </em><em>that</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>exactly</em><em> </em><em>divisible</em><em> </em><em>by</em><em> </em><em>1</em><em> </em><em>and</em><em> </em><em>itself</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>prime</em><em> </em><em>number</em><em>. </em>
<em>2</em><em> </em><em>is</em><em> </em><em>divisible</em><em> </em><em>by</em><em> </em><em>1</em><em> </em><em>and</em><em> </em><em>2</em>
<em>prime</em><em> </em><em>number</em><em> </em><em>has</em><em> </em><em>only</em><em> </em><em>two</em><em> </em><em>factors</em><em>. </em>
<em>FOR</em><em> </em><em>Example</em><em>:</em><em> </em><em>13</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
Answer: Part A is 2 and 6 Part B is 2
Step-by-step explanation:
Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.
Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8. 3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.
Answer:
1.526
Step-by-step explanation:
12-2x-9x-2 = 4+8x-32
-11x+10 = 8x-28
-19x = -29
x = 1.526
7h + 6b = 35.50
5h + 6b = 30.50
The difference between the 2 totals spent is $5, and there were the same number of burgers, but 2 fewer hotdogs. So $5/2 = $2.50, the cost of a hot dog. Substitute that into the equations to solve for burgers (b)
5(2.50) + 6b = 30.50
12.50 + 6b = 30.50
6b = 18
b = 3
Check the work:
7(2.50) + 6(3) =
17.50 + 18 = 35.50
P. o. symm is at (-3, -1) it is the center of the circle.