Answer:
43.17 ft/s
Step-by-step explanation:
Let the height of the wall is y.
distance of wall from light is 20 feet.
y = 20 tanθ .... (1)
time period, T = 3 second
Differentiate equation (1) with respect to t.
dy/dt = 20 x 2.16
dy/dt = 43.17 ft/s
Answer:
24 or 25, because of the max height it can reach on the graph, its reaching the maximum height it can go
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Answer:
x=3
Step-by-step explanation:
Answer:
24.58
Step-by-step explanation: