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horsena [70]
1 year ago
8

What theorem states that if two sides and the included angle of one triangle are congruent to the corresponding parts of another

triangle the triangles are congruent?
Mathematics
1 answer:
lianna [129]1 year ago
7 0

The given statement is proved by side-angle-side (SAS) theorem.

Yes, if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle the triangles are congruent.

The statement is proved by SAS theorem

<u>Side-Angle-Side (SAS) theorem: </u>

The triangles are congruent if two sides and the included angle of one triangle are equivalent to two sides and the included angle of another triangle.

Hence, The given statement is proved by side-angle-side (SAS) theorem.

To read more about Angles

brainly.com/question/22472034

#SPJ4

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To build a computer,your need to buy a motherboard for 120 dollars,a CPU for 100 dollars.RAM memory for 45 dollars,storage for 3
patriot [66]

Answer:

  $3450

Step-by-step explanation:

The cost of one computer is the sum of the cost of the parts:

  $120 +100 +45 +30 +50 = $345

Then the cost of 10 of them is ...

  10 × $345 = $3450 . . . . cost for 10 computers

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The graph below is correct for the linear equation y=-3. <br><br> True<br> False
Oksana_A [137]

Answer:

False.

Step-by-step explanation:

The graph that is shown is correct for the equation x= -3. The graph for y= -3 would run vertically, not horizontally.

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The function t(x)=3x+1 determines how many cans of green beans a food truck needs to stock on board, where x is the number of sh
artcher [175]

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Please help me with this!!!!!
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Answer:

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Step-by-step explanation:

To solve, let's find the missing angle of the triangle:

180 - 120 - 15 = 45°

That means a solution should have at least 2 solutions from the solution set (15 , 45, 120)

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John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
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