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Akimi4 [234]
3 years ago
9

How to find the mean and the median

Mathematics
2 answers:
maria [59]3 years ago
7 0

The mean you have to add up your numbers first then divide them by the amount of numbers you have .ex. 1+2+3 is 6 then divide so 6÷3 =3   Median is the middle number in list. So put them in order then muddle number is your median. If you have two numbers left add them and divide by 2. That will be your median.

tekilochka [14]3 years ago
7 0
Mean: The "average" number; found by adding all data points and dividing by the number of data points.
Example: The mean of 4, 1, & 7 is (4+1+7)/3 = 12/3= 4
Median: The middle number; found by ordering all data points and picking out the one in the middle (or if there are two middle numbers, taking the mean of those two numbers).
Example: The median of 4, 1, & 7 is 4 bc when the numbers are put in order (1, 4, 7), the number 4 is in the middle.
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F(x) = Vx - 14. Find the inverse of f(x).
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b

Step-by-step explanation:

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Marcus monthly salary is $1,500 plus 10% of sales. How much could Marcus earn per month with salary and 9% sales? Please explain
sergejj [24]

If Marcus monthly salary is $1,500 plus 10% of sale, then he could earn 1500 + 0.09x per month with salary and 9% sales

Monthly salary of Marcus = $1500

The percentage incentives for sales = 10%

If the percentage of incentive for sales is 9 %

Consider the amount of sales is $x

Therefore the monthly salary of Marcus = Monthly salary of Marcus + (The amount of sales × 9/100)

Substitute the values in the equation

The monthly salary of Marcus = 1500 + (x×9/100)

Divide the numbers in the equation

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Multiply the numbers the numbers

= 1500 + 0.09x

Therefore, the monthly salary of Marcus will be 1500 + 0.09x

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OLEGan [10]
A) y= -2, 3, 7


B) y= 8, 0, -6


C) y= -8, 1, 7


d) y= 1, -2, -6

7 0
3 years ago
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Which is greater 3/5, 33/50, 303/500, 3,003/5,000, 30,003/50,000
ad-work [718]

33/50 because it is biggest

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A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n
Ratling [72]

Answer:

a)

k = \dfrac{1}{21}

b) 0.476

c) 0.667    

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

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\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}

b) at most four forms are required

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c) probability that between two and five forms (inclusive) are required

P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667

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