Answer:
Step-by-step explanation:
x+y=10
x=10-y
x=10-5
x=5
3y= -3x+30
3(10-y)= -3(10-y)+30
30-3y= -30+3y+30
30+30-30=6y
30=6y
y=5
Solve for x:
8 - 5 x = 2 x + 8
Subtract 2 x from both sides:
8 + (-5 x - 2 x) = (2 x - 2 x) + 8
-5 x - 2 x = -7 x:
-7 x + 8 = (2 x - 2 x) + 8
2 x - 2 x = 0:
8 - 7 x = 8
Subtract 8 from both sides:
(8 - 8) - 7 x = 8 - 8
8 - 8 = 0:
-7 x = 8 - 8
8 - 8 = 0:
-7 x = 0
Divide both sides of -7 x = 0 by -7:
(-7 x)/(-7) = 0/(-7)
(-7)/(-7) = 1:
x = 0/(-7)
0/(-7) = 0:
Answer: x = 0
The point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Given: k(x) = 5x - 1, h(x) = -3x - 1
We need to find the point(if any) at which these two lines k and h meets.
To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.
Therefore, k(x) = h(x)
=> 5x - 1 = -3x - 1
=> 8x = 0
=> x = 0
k(x=0) = 5 * 0 - 1 = -1
Hence the point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Know more about "point of intersection" problems here: brainly.com/question/16929168
#SPJ1
Answer: 5x3 + x2 - 2x + 5
Make sure to combine like terms and watch out for if it’s subtraction or addition.
