The value of x in the congruent triangles abc and dec is 1
<h3>How to determine the value x?</h3>
The question implies that the triangles abc and dec are congruent triangles.
The congruent sides are:
ab = de
bc = ce = 4
ac = cd = 5
The congruent side ab = de implies that:
4x - 1 = x + 2
Collect like terms
4x - x = 2 + 1
Evaluate the like terms
3x = 3
Divide through by 3
x = 1
Hence, the value of x is 1
Read more about congruent triangles at:
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<u>Complete question</u>
Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
Y=8
your teacher is introducing algebra
Answer:
15
Step-by-step explanation:
the formula for area of a parallelogram is base times height
Answer:
-12x+18x²
Step-by-step explanation:
Given: 
Distributive property of multiplication under which a number is multiplied by the sum of two number, the first number can be distributed to both of those number.
∴
solving it by using distributive property
= 
= 
Opening parenthesis
= 
Hence, -12x+18
is the result after using distributive property.
You multiply 8 by 15 then again by 6 so the answer is 720
