<u>Given</u> that Richard and Teo have a combined age of 46.
Richard is 13 years older than twice Teo's age.
We need to determine the age of Richard and Teo.
<u>Equation:</u>
Let x denote Richard's age.
Let y denote Teo's age.
Let us write the ages in the form of equation.
Thus, we have;
and
![x=13+2y](https://tex.z-dn.net/?f=x%3D13%2B2y)
<u>Solving the equations:</u>
The ages of Richard and Teo can be determined by solving the two equations using substitution method.
Hence, substituting
in the equation
, we get;
![13+2y+y=46](https://tex.z-dn.net/?f=13%2B2y%2By%3D46)
![13+3y=46](https://tex.z-dn.net/?f=13%2B3y%3D46)
![3y=33](https://tex.z-dn.net/?f=3y%3D33)
![y=11](https://tex.z-dn.net/?f=y%3D11)
Thus, the value of y is 11.
Now, substituting
in the equation
, we get;
![x+11=46](https://tex.z-dn.net/?f=x%2B11%3D46)
![x=35](https://tex.z-dn.net/?f=x%3D35)
Thus, the value of x is 35.
<u>Age of Richard and Teo:</u>
Thus, the values of x and y are 35 and 11 respectively.
Since, x denote Richard's age and y denote Teo's age, substituting the values, we have;
The age of Richard is 35 years old and the age of Teo is 11 years old.