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nydimaria [60]
3 years ago
5

The moon is almost directly between the sun and earth

Computers and Technology
2 answers:
brilliants [131]3 years ago
8 0
Only in a solar eclipse otherwise no
anastassius [24]3 years ago
3 0
That's true for a few days out of a month ... a day or two before and after each New Moon. When it does actually get DIRECTLY between, that's when we get a solar eclipse.
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Web pages are accessed through a software program called a _____.A) ​web crawlerB) ​web browserC) ​web serverD) ​web app drawer
IrinaVladis [17]

Answer: B) ​web browser

Explanation: A web browser may be explained as a software program or application available on various operating systems such as windows, Mac, Android, iOS among others. This program acts as an interface between information available on websites or pages and users. This application takes a specified uniform resource locator or web address as input and outputs the information available on a web page. Google Chrome, Internet Explorer, Microsoft edge, opera mini, Safari, Firefox and so on.

3 0
3 years ago
Java:
Agata [3.3K]

Answer:

import java.util.*;

public class work {

// function for counting unique character

public static int numUnique(String input) {

boolean[] list = new boolean[Character.MAX_VALUE];

for (int i = 0; i < input.length(); i++) {

list[input.charAt(i)] = true;

}

int count = 0;

for (int i = 0; i <list.length; i++) {

if (list[i] == true){

count++;

}

}

return count;

}

public static void main(String args[])

{

List<String>list=new ArrayList<>(); // creatng array list of type string

list.add("abcdef");

list.add("aaabcd");

list.add("bccddee");

list.add("abcddd");

list.add("a");

for(String str:list)

{

// for printing the results

System.out.println("given string : "+ str+" , number of unique values :"+numUnique(str));

}

}

}

Explanation:

5 0
4 years ago
Create an application named TestClassifiedAd that instantiates and displays at least two ClassifiedAd objects. A ClassifiedAd ha
arlik [135]

Answer:

Following is given the code with all necessary descriptions as comments in it. The output is also attached under the code. I hope it will help you!

Explanation:

5 0
3 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
Use the drop-down menu to complete the steps for using the Autofill feature. Click the . Click the . Drag the to the desired ran
nlexa [21]

Answer:

Cell,fill handle,fill handle

Explanation:

Trust

8 0
3 years ago
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