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AnnyKZ [126]
3 years ago
13

When you press on the gums, release the pressure, and then measure the time it takes for the gums to return to the starting colo

r, you're checking
Biology
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

Capillary refill time

Explanation:

Capillary refill time refers to the time that it takes for color to return to an external capillary bed after pressure has been applied (which causes blanching). Usually, on healthy individuals, capillary refill time takes less than 2 seconds. If the time is much longer, this could indicate problems such as shock, dehydration or peripheral artery disease.

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Describe the adaptations of the mammalian kidney to selective reabsorption<br><br>​
Anvisha [2.4K]

Answer: The tubule is long and highly coiled to provide a large surface area for selective reabsorption. The coiling of the tubule reduces the speed of the flow of the filtrate to give more time for efficient reabsorption. The tubule is well supplied with blood capillaries to increase a steep diffusion gradient for selective re-absorption.

Explanation: Selective reabsorption occurs because during ultrafiltration, important components of the blood are filtered out and they need to be reabsorbed into the body.

4 0
2 years ago
A hypothesis must be
insens350 [35]
A hypothesis MUST be testable.
3 0
2 years ago
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A plant is placed near a window. Instead of growing straight up, the plant grows to the side. What is this plant demonstrating?(
Gemiola [76]

Answer:

Phototrophism

Explanation:

The plant is growing towards the light. this is an example of phototrophism.

6 0
2 years ago
The Great Electron Chase: Describe the flow of electrons from rain falling on your strawberry garden into the strawberry plant (
JulijaS [17]

Answer:

As the rain water is absorbed by the strawberry roots to the leaves, the first step of light independent stage of photosynthesis; Photolysis takes place.

                               H20 = 2H+ + 2e + 2O2.

Generally, the chlorophyll is made up of primary and accessory pigments in its photosystems I and II. These photosystems emitted their electrons through photo activation; these are picked up by electron acceptors; for photophosphorylation in ATPs synthesis. Therefore, these photosystems are positively charged. Hence, PI takes electrons from P II (since it is Cyclic photophosphorylation).Thus P1 is now stabilized, why PII is unstable. To regain its stability, it replaces its lost electrons from the electron of photolysis of water above. This is the electron from the rain water on the (stored in chlorophyll) strawberry. The electron from PI combines with H+and picked up by NAD to NADH. (2H+2e+NADP= NADH).

When the strawberry is consumed, it undergoes digestion and its cellulose metabolized to glucose (the electrons are trapped in the elements C,H,O in the glucose) which flows into the blood stream. As the individual undergoes cellular respiration the glucose with its electrons are the substrate. The glucose, undergoes substrate level phosphorylation (Glycolysis).These electrons are transferred from glucose to the new elements in pyruvate as glucose moves from one stage to another. The electrons are also transferred as part of  H picked up by NAD to NADH. They are transferred from pyruvate to Acetyl, as the latter forms Acetyl Co A with coenzyme A.  

The Acetyl CoA, enters the Krebs’s Cycle, and as, moves from one step to another, these electrons are transferred from one intermediate to another. They are eventually transferred by NADH, FADH2 into the matrix of the mitochondria, where they splits from hydrogen atoms, and carried by electron carriers. As they move from one carries to another, PMF is generated which pumps the H+ across into the inner membranes, to generate the electrochemical gradients for ATPs synthesis, as the protons returns to the matrix.

When these electrons reached the end of the carrier molecule, they are accepted by oxygen the final electron acceptor, to form water. These electrons is transported as water, to the kidney where they are pass through the stages of glomerular filtration, reabsorption, secretion before they are emptied in urine as waste.  

Explanation:

4 0
3 years ago
When considering an RBC histogram, what can cause an elevation in the left side of the curve?
stepladder [879]

Answer:

Low mean corpuscular value can shift the curve to the left side.

Explanation:

RBC histogram may be defined as the process of plotting the number of blood cells on Y- axis and their relative size on X- axis. Modern automated haematology is used for the construction of RBC histogram.

The cell population of RBCs is similar in size but not equal to the size of RBC the curve can shift to either direction. The low MCV (mean corpuscular value) value can shift the the curve to the left side while considering an RBC histogram.

7 0
3 years ago
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