Ax^2+bx+c
if a=1, then
take 1/2 of b and square it
w^2-4w+c
b=-4
-4/2=-2, (-2)^2=4
add that
w^2-4w+4
(w-2)(w-2)
(w-2)^2
to make it into perfect squres, add 4
-7 1/8 - (-9 1/2) =
-7 1/8 + 9 1/2
-7 + 9 = 2
-1/8 + 1/2 = -1/8 + 4/8 = 3/8
answer is : 2 3/8 (or 19/8)
Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer:
2x + 2
Step-by-step explanation:
Given
( divide each term on the numerator by x )
= x² + 2x
Differentiate each term using the power rule
(a ) = na , then
(x² + 2x ) = 2x + 2