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NikAS [45]
3 years ago
12

What is the Inverse operation for sin

Mathematics
2 answers:
Sonbull [250]3 years ago
8 0
Arcsine

You’re Welcome :)
katen-ka-za [31]3 years ago
3 0

Answer:

arcsin function

Step-by-step explanation:

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Elenna [48]

Answer:

like write an equation? If so it's a 0 slope

Step-by-step explanation:

6 0
3 years ago
The matrix below represents a system of equations.
noname [10]

Answer:

The first choice: a = 1, b = -1, and c = 2.

Step-by-step explanation:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 1 & -1 & -2 \cr 1 & 0 & -3 & -5\end{array} \right].

Add the first row to the second row to obtain:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 2 + 1 & (-1) + 1 & 1 + (-1) & 5 + (-2) \cr 1 & 0 & - 3& -5\end{array} \right].

Simplify that matrix to obtain:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 3 & 0 & 0 & 3\cr 1 & 0 & -3 & -5\end{array} \right].

Divide the second row by 3:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 1 & 0 & -3& -5\end{array} \right].

Hence, a = 1.

Subtract the current row two from row three:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 1 - 1 & 0 & -3 & (-5)- 1 \end{array} \right].

Simplify that matrix to obtain:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 0 & 0 & -3 & -6 \end{array} \right].

Invert the signs in the third row and divide it by 3 to obtain:

\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 0 & 0 & 1 & 2 \end{array} \right].

Hence, c = 2.

Subtract two times the current second row from the first row to obtain:

\left[ \begin{array}{ccc|c} 2 - (2 \times 1) & -1 & 1 & 5 - 2\times 1\cr 1 & 0 & 0 & 1\cr 0 & 0&1 & 2 \end{array} \right].

That simplifies to

\left[ \begin{array}{ccc|c} 0 & -1 & 1 & 3\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right].

Subtract the current third row from the first row to obtain:

\left[ \begin{array}{ccc|c} 0 & -1 & 1-1 & 3-2\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right].

That simplifies to

\left[ \begin{array}{ccc|c} 0 & -1 & 0& 1\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right].

Invert the signs in the first row to obtain:

\left[ \begin{array}{ccc|c} 0 & 1 & 0& -1\cr 1& 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right].

Hence, b = -1.

\left[ \begin{array}{ccc|c}1& 0 & 0 & 1 \cr0 & 1 & 0& -1 \cr 0 & 0 & 1& 2\end{array} \right].

3 0
4 years ago
a 29 gram sample of a substance that's used to preserve fruits and vegetables has a k-value of 0.1359. Find the substance's half
kaheart [24]
Okay well
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t

now, find the half, set a(t)= half the original and solve for t

14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t

t=in(0.5)/(-0.1359)= (aprox) 5.1 days

6 0
4 years ago
Read 2 more answers
Factor the common factor out of each expression. PLEASE HELP ITS DUE TONIGHT!!!
madam [21]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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How to know if something is proportional on a table? Pls it’s due today pls answer I just need a formula
Musya8 [376]
Yes they are proportional



Formula:


-20/-15 = x/6

If you solve this equation for x it should evaluate to x = 8 which indicates it is proportional.

Notice the position of -20, -15, 6, and 8 in the chart and in the fraction
4 0
4 years ago
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