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Kisachek [45]
3 years ago
10

Marty ate 4/6 of his pizza and Luis ate 5/6 of his pizza. Marty ate more pizza than Luis . How is that possible?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0
Marty's pizza had a bigger radius that Luis' pizza had.

1% of a battleship is more steel than 98% of a car.
Sauron [17]3 years ago
3 0
Maybe because Marty had a different sized pizza. Maybe he had a large and its cut into 6ths,and Luis had a small cut into 6ths? Maybe idk.
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(x^3+10x^2+2)/(x+10)
SCORPION-xisa [38]

The quotient is x^2

The remainder is 2

Step-by-step explanation:

We need to divide: \frac{\left(x^3+10x^2+2\right)}{x+10}

The division is shown in figure attached.

The quotient is x^2

The remainder is 2

Keywords: Division of polynomials

Learn more about Division of polynomials at:

  • brainly.com/question/4390083
  • brainly.com/question/4786449

#learnwithBrainly

8 0
3 years ago
A.Sum of integer and its additive inverse is ___________.B.Sum of -22 and -44 is ______________.C.-36 ÷ ( ___)=-9d._________ is
Ede4ka [16]

Answer:

  A. 0

  B. -66

  C. 4

  D. 998

  E. -12

Step-by-step explanation:

A. By definition, the sum of anything and its additive inverse is zero.

__

B. If you have trouble with sums, your calculator can help.

  -22 + (-44) = -22 -44 = -66

__

C. -36/x = -9 can be solved by multiplying by x and dividing by -9:

  -36 = -9x

  -36/-9 = x = 4

Since the product of the divisor and quotient is the dividend, dividing the dividend by either gives the other. Here, your dividend is -36 and your quotient is -9. To find the divisor, you can divide -36 by -9, as we did.

__

D. The absolute value function changes the sign of negative numbers to positive:

  |-998| = 998

__

E. If you have trouble with sums, your calculator can help.

  (−2)−[(−3)−(−7)−(−6)]

  = -2 -(-3 +7 +6) = -2 -10 = -12

4 0
2 years ago
139°<br> (17x + 3)<br> answer
nasty-shy [4]

Answer:

x= 8

Step-by-step explanation:

17x + 3 = 139

17x = 136

x = 8

6 0
2 years ago
Solve for x. Round to the nearest tenth, if necessary.
Sphinxa [80]

Answer:

2.8

Step-by-step explanation:

tan = opposite / adjacent

( opposite = side opposite of the angle and adjacent = side length that is not the opposite nor the hypotenuse ( longest side ) )

we are given an angle, ∠E = 26°

tanE = x / 5.7

tan26 = x / 5.7

==> multiply both sides by 5.7

5.7tan26 = x

==> simplify

x = 2.8 ( rounded )

3 0
1 year ago
What is the completely factored form of f(x)=x^3-7x^2+2x+4
xxMikexx [17]

Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)

Steps:

x^3-7x^2+2x+4

Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}

\frac{x^3-7x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}

\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4

\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

8 0
2 years ago
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