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Ludmilka [50]
3 years ago
15

A group of 18 people ordered soup and sandwiches for lunch. Each person in the group had either one soup or one sandwich. The sa

ndwiches cost $7.75 each and the soups cost $4.50 each. If the total cost of all 18 lunches was $113.50, how many sandwiches were ordered?
a. 7B. 8C. 9D. 10
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
6 0
X - the number of sandwiches
y - the number of soups

x+y=18 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\times (-4.5) \\
7.75x+4.5y=113.5 \\ \\
-4.5x-4.5y=-81 \\
\underline{7.75x+4.5y=113.5} \\
7.75x-4.5x=113.5-81 \\
3.25x=32.5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\div 3.25 \\
x=10

10 sandwiches were ordered. The answer is D.
Julli [10]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

m=\frac{y2-y1}{x2-x1}

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so

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substitute equation B in equation A

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therefore

The ordinate of B exceeds the ordinate of A by 7

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