Answer:
f = 2
g = 8
h = -9
k = 40
m = 1
Step-by-step explanation:
Equation 1:
23f - 17 = 29
Add 17 to both sides. This undoes the -17.
23f = 29 + 17
Add 17 to 29 to get 46.
23f = 46
Divide both sides by 23. This undoes the multiplication by 23.
f = 46/23
Divide 46 by 23 to get 2.
f = 2
Equation 2:
2(3g + 4) = 56
Divide both sides by 2. This undoes the multiplication by 2.
3g + 4 = 56/2
Divide 56 by 2 to get 28.
3g + 4 = 28
Subtract 4 from both sides. This undoes the +4.
3g = 28 - 4
Subtract 4 from 28 to get 24.
3g = 24
Divide both sides by 3. This undoes the multiplication by 3.
g = 24/3
Divide 24 by 3 to get 8.
g = 8
Equation 3:
h + 9 = 0
Subtract 9 from both sides. This undoes the +9.
h = 0 - 9
Any number subtracted from 0 gives its negation.
h = -9
Equation 4
3(k - 8) = 96
Divide both sides by 3. This undoes the multiplication by 3.
k - 8 = 96/3
Divide 96 by 3 to get 32.
k - 8 = 32
Add 8 to both sides. This undoes the -8.
k = 32 + 8
Add 8 to 32 to get 40.
k = 40
Equation 5:
5m - 5 = 0
Add 5 to both sides. This undoes the -5
5m = 0 + 5
Anything plus 0 gives itself.
5m = 5
Divide both sides by 5. This undoes the multiplication by 5
m = 5/5
Anything divided by itself gives you 1.
m = 1
The complete table will be:

<u><em>Explanation</em></u>
Suppose, the number of sit-ups in Sunday is 
Mean is the simple average of some numbers. <u>For finding the mean number</u> of sit-ups per day, we need to <u>divide the 'total number of sit-ups' by the 'total number of days'</u>.
Here the total number of days is 7 and the total number of sit-ups for 7 days 
Given that, the mean number of sit-ups per day is 100. So, the equation will be...

So, the number of sit-ups you have to do Sunday is 175.
Answer:
498020 miles al
Step-by-step explanation:
Use division or long division (ignore the decimal point)
Then put the decimal in the same spot as the dividend (the number being divided)
Answer:
0.049168726 light-years
Step-by-step explanation:
The apparent brightness of a star is
where
<em>L = luminosity of the star (related to the Sun)
</em>
<em>d = distance in ly (light-years)
</em>
The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.
Hence the apparent brightness of Alpha Centauri A is
According to the inverse square law for light intensity
where
light intensity at distance
light intensity at distance
Let
be the distance we would have to place the 50-watt bulb, then replacing in the formula
Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.