The range of a function is the set of all values that it can take when its independent variable takes values on the domain.
On the other hand, the range of a function is the domain of its inverse function, if that inverse exists, and vice-versa: the domain of a function is the range of its inverse function, if that inverse exists.
In the case of the given equation:
The inverse function exists since the function is linear, and it can be found by isolating <em>x</em>:
If the range of the original function is the set given by the number {
Answer:
Option C.
The distance from the point to the circle is 6 units
Step-by-step explanation:
we know that
The distance between the circle and the point will be the difference of the distance of the point from the center of circle and the radius of the circle
step 1
Find the center and radius of the circle
we have
Convert to radius center form
Complete the square
Rewrite as perfect squares
so
The center is the point (0,4)
The radius is
step 2
Find the distance of the point from the center of circle
the formula to calculate the distance between two points is equal to
we have
(6,-4) and (0,4)
substitute the values
step 3
Find the difference of the distance of the point from the center of circle and the radius of the circle
therefore
The distance from the point to the circle is 6 units
see the attached figure to better understand the problem
Answer: k= -1
Step-by-step explanation: cant to quadratic as it is not in standard form
Answer:
D
Step-by-step explanation:
Its an abs value so you have to solve twice. Once for d - 3.5 < or equal to 1.5 which equals 5. You also have to solve for d - 3.5 > or equal to -1.5 which equals 2. So on the graph it has to be less than 5 and greater than 2 so you just connect the two and draw the line over the numbers in between the 2 and 5.
For part 8-71,
a) 2=105
b) 2=55
c) 2=53
d)2=160
