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Nikitich [7]
2 years ago
14

How can we simplify the expression -(1-5n)-7n

Mathematics
1 answer:
dsp732 years ago
5 0
-(1-5n)-7n \\ \\ -1 + 5n - 7n \\ \\ -1 - 2n \\ \\ Answer: \fbox {-1 - 2n}
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The expression (2x^2)^3 is equivalent to _____.<br><br> 6x^2<br> 6x^5<br> 8x^6
4vir4ik [10]

Answer:

8x^{6}

Step-by-step explanation:

To solve this problem is multiply 2 by 2 and then 2 which gives you 8.

Then you will add 2+2+2 and get six. For when multiply exponents you are adding.

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3 years ago
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I NEED THIS ANSWER NOW! Determine which postulate or theorem can be used to prove that ABC DCB.
Archy [21]
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Proof
AC = DB
AB = DC
BC = BC This side is equal to itself and is common to both triangles.

Three sides of one triangle equal to 3 sides of the other means that the triangles are congruent. It is the Theorem you need.
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2 years ago
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Someone answer and explain PLEASE ILL MARK BRAINLIEST
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Answer:

i beleive 9 times

Step-by-step explanation:

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2 years ago
A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing sa
Paraphin [41]

Answer:

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 220, \sigma = 13, n = 35, s = \frac{13}{\sqrt{35}} = 2.1974

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

0.643 = \frac{X - 220}{2.1974}

X - 220 = 0.643*2.1974

X = 221.41

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

Z = \frac{X - \mu}{s}

-0.643 = \frac{X - 220}{2.1974}

X - 220 = -0.643*2.1974

X = 218.59

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

5 0
3 years ago
olivia purchases gifts for her mom and grandma for mother's day. The first is a pair of sunglasses for $16.35 and the second is
PolarNik [594]
$23.40

Since we know how much Olivia spent total, and we know how much she spent on the sunglasses, we just subtract 16.35 from 39.74, and the final answer is 23.40
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3 years ago
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