10 hours to 6 hours find the percent of change

Solve 110 = 10p. p = 12 p = 100 p = 120 p = 11

Temka [501]

You would need to divide both sides by 10.
110=10p
11=p

6 0

3 years ago

Integers and polynomials are both _[blank 1]_ under addition, subtraction, and multiplication; however, operations on polynomial

geniusboy [140]

Answer:

Integers and polynomials are both closed under addition, subtraction, and multiplication; however, operations on polynomials can sometimes be open while operations on integers produce irrational results .

Step-by-step explanation:

Closed means that addition, subtraction, and multiplication of integers gives as result a new integer; and addition, subtraction, and multiplication of polynomials gives as result a new polynomial.

Operations on polynomials can sometimes be open, like in division.

Operations on integers can produce irrational results , for example, dividing 11 by 9.

5 0

3 years ago

Find an equation of the sphere with points P such that the distance from P to A(−3, 4, 4) is twice the distance from P to B(6, 3

NeX [460]

Answer:

Therefore, we conclude that the center of sphere at point

(27/3, -8/3, -8/3) with a radius 6.89.

Step-by-step explanation:

We have the formula for distance, we get

\sqrt{(x+3)^2+(y-4)^2+(z-4)^2} =2· \sqrt{(x-6)^2+(y-3)^2+(z+1)^2}

(x+3)^2+(y-4)^2+(z-4)^2=4·[(x-6)^2+(y-3)^2+(z+1)^2]

x²+6x+9+y²-8y+16+z²-8z+16=4x²-48x+4y²-24y+4z²+8z+184

3x²+3y²+3z²-54x+16y+16z=-143

(x²-54x/3)+(y²+16y/3)+(z²+16z/3)=-143/3

(x²-54x/3+729/9)+(y²+16y/3+64/9)+(z²+16z/3+64/9)=-143/3+729/9+2·64/9

(x-27/3)²+(y+8/3)²+(z+8/3)²=428/9

We calculate a radius \sqrt{428/9} =6.89

Therefore, we conclude that the center of sphere at point

(27/3, -8/3, -8/3) with a radius 6.89.

7 0

3 years ago

A 12-cm-long thin rod has the nonuniform charge density λ(x)=(2.0 nC/cm)e−|x|/(6.0 cm), where x is measured from the center of t

Inessa [10]

Answer:

the total charge is

$Q=24(1-\exp(-1))nC\approx15.171nC$

Step-by-step explanation:

Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated as

$Q=\int^{6}_{-6}2\exp\left(\frac{-|x|}{6}\right)dx$

separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we get $Q=\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx+\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

using the substitution x=-u in the first integral we get $\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx=-\int^{0}_{6}2\exp\left(\frac{-u}{6}\right)du=\int^{6}_{0}2\exp\left(\frac{-u}{6}\right)du$

which is the same as the first integral. Thus, the total charge is given by

$Q=2\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

integrating we get

$Q=4(-6\exp\left(\frac{-x}{6}\right))\big|^{6}_{0}=-24(\exp(-6/6)-\exp(0))=24(1-\exp(-1))$

4 0

3 years ago

Why is (3,-5) not a solution to -x+4y=-15

Olegator [25]

C) It doesn’t satisfy either the top or bottom equations.

When we plug them into the top equation:
$- 3 + 4( - 5) = - 15$
Simplify:
$- 3 + ( - 20) = - 15 \\ \\ - 23= - 15$
Because the statement of -23 = -15 is wrong, the solution pair is wrong for the top equation.

When we plug them into the bottom equation:
$- 2(3) - 3( - 5) = - 8$
Simplify:
$- 6 - ( - 15) = - 8 \\ \\ 9 = - 8$
9 = -8 is not a valid statement, so the pair doesn't satisfy both of the equations.

3 0

3 years ago