43:
   Negative temperatures are basically the same as normal ones, although they go below zero, so they are still the same distance apart from zero, just on the left side of the number line.

      To find the answer find the difference between 30.5°C and 0 (which is 30.5).

      Next, find the difference between -122.2°C and zero (122.2)

   Finally, add 122.2 + 30.5 to find the total distances from the zero combined for the full distances apart from each other.

   (We add them because -122.2 to the left of zero, and 30.5 is on the right)

      You should get 152.7 as your answer.

45:
   I'm guessing since it is asking for the deepest point (-5315) from sea level (0), the answer is -5,315 feet

   *Remember 5,315 is negative because numbers below sea level are all negative*

   So the answer should be -5,315 feet deep. (I'm not sure how to show your work for that I'm guessing it is 0 - 5,315 at the slightest).

*Hope this all helped :)*

5 0

3 years ago

Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro

umka21 [38]

$|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%$

8 0

3 years ago

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