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3 years ago

Which equation describes the line passing through (4,-2) with a slope of 1/2

1 answer:

3 0

   y - y₁ = m(x - x₁)
y - (-2) = ¹/₂(x - 4)
   y + 2 = ¹/₂(x) - ¹/₂(4)
   y + 2 = ¹/₂x - 2
      - 2    - 2
   y = ¹/₂x - 4

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What added to what equals -9

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4 years ago

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Write the equation in standard form for the circle passing through ( - 2,0) centered at the origin.

Aleks04 [339]

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3 years ago

Please help I need help

JulijaS [17]

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3 years ago

form a polynomial function whose real zeros are -2 with multiplicity 2 and 4 with multiplicity 1 whose degree is 3

NeTakaya

Answer:

$f(x) = {x}^{3} -12x - 16$

Step-by-step explanation:

We want to for a polynomial function whose real zeros are -2 with multiplicity 2 and 4 with multiplicity 1.

If -2 is a zero of a polynomial, then by the factor theorem, x+2 is a factor.

Since -2 has multiplicity 2, (x+2)² is a factor.

Also 4 is a zero which means x-4 is a factor.

We write the polynomial in factored form as:

$f(x) = {(x + 2)}^{2} (x - 4)$

We expand to get:

$f(x) = ({x}^{2} + 4x + 4)(x - 4)$

We expand further to get:

$f(x)=x({x}^{2} + 4x + 4) - 4({x}^{2} + 2x + 4)$

$f(x) = {x}^{3} + 4 {x}^2 + 4x - 4 {x}^{2} + 8x - 16$

$f(x) = {x}^{3} - 12x - 16$

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3 years ago

Solve x/2 - 3 = 7. 5 10 20 40

earnstyle [38]

<span> x/2 - 3 = 7
Add 3 to both sides
x/2=10
Multiply 2 on both sides
Final Answer: B. 20</span>

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3 years ago

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