Question

What are the x-intercepts of y=sin(x)+1

Answer 1

Answer:

$x = n\pi + ( { - 1)}^{n} \times \frac{3\pi}{2}$

Step-by-step explanation:

We want to find the x-intercepts of

$y = \sin(x) + 1$

At x-intercept, y=0.

$0 = \sin(x) + 1$

$\sin(x) = - 1$

Take sine inverse of both sides to get:

$x = { \sin }^{ - 1} ( - 1)$

$x = n\pi + ( { - 1)}^{n} { \sin }^{ - 1} ( 1)$

The x-intercepts are:

$x = n\pi + ( { - 1)}^{n} \times \frac{3\pi}{2}$

for n being an integer