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Tomtit [17]
3 years ago
10

Select the two values of x that are roots of this equation. 2x^2-11x+15=0

Mathematics
2 answers:
scZoUnD [109]3 years ago
6 0

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>x₁ = 5/2</em>

<em>x₂ = 3</em>

▹ Step-by-Step Explanation

2x² - 11x + 15 = 0

2x² - 5x - 6x + 15 = 0

x(2x - 5) - 6x + 15 = 0

x(2x - 5) - 3(2x - 5) = 0

(2x - 5) * (x - 3) = 0

2x - 5 = 0

x - 3 = 0

x₁ = 5/2

x - 3 = 0 → x₂ = 3

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

zaharov [31]3 years ago
4 0

Hey there! :)

Answer:

x = 5/2 and 3.

Step-by-step explanation:

Factor the equation. Find numbers that will sum up to -11 involving the coefficient of 2, and that multiply into 15.

2x² - 11x + 15 = 0

(2x - 5)(x - 3) = 0

Use the Zero Product Property to solve for the roots of this equation:

2x - 5 = 0

2x = 5

x = 5/2

----------

x - 3 = 0

x = 3.

Therefore, the two values of x that are roots of this equation are:

x = 5/2 and 3.

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<h2 />

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\cos( - 1)  ( \cos(43°))

  • <u>simplify</u><u> the</u><u> expression</u><u> </u><u>us</u><u>i</u><u>Ng the </u><u>symmetry</u><u> of</u><u> </u><u>trigonometry</u>

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