Ill tell you the answer if u mark me brainliest
Answer:
Answer:
For converging lens
object distance u = - 2.0cm
Focal length f = 5.0cm
From lens formula
m=
m=
=3
Size of image = size of object x Magnification
= 2 x .10 = 2.0cm
For diverging lens
object distance u = 140 - 120 = 20 cm
focal length f = -30 cm
frac{1}{v}+\frac{1}{20}=-\frac{1}{30}
v = -12 cm
m = 12/20 = 0.6
size of final image = .6 x 30 = 18 cm
Answer:
Depends on amount of students.
Step-by-step explanation:
You would just multiply the amount of students time (1 1/2) = (1.5)
Ex:
3 students 4 1/2 hours
4 students 6 hours
5 students 7 1/2 hours
and so on
